The resulting equation has a leading degree of 2, hence the system of equation will have 2 solutions
<h3>Quadratic equations</h3>
Quadratic equations are equations that has a leading degree of 2. Given the following system of equations
y=2x
y=x^2+2
Equate to have:
2x = x^2+ 2
Equate to zero
x^2 - 2x +2 = 0
Since the resulting equation has a leading degree of 2, hence the system of equation will have 2 solutions
Learn more on system of equations here: brainly.com/question/14323743
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Answer:
1. No pattern 2. negative nonlinear 3. Variables don't seem related 4. many outliers
Step-by-step explanation:
perimeter should be 43 and the area should be 72m^2
this is squared btw
3(x-1)^2 +2
This is your answer in vertex form, your h and k values are the vertex. Solving the function by using b/2a, we get that h is 1. ( in the equation 3 is your a, 6 is b and 5 is c.). ( 6/2(3)) = 1. We can then plug in 1 as x into the original equation and get positive 2 ( 3(1)^2 -6(1) +5) = 3-6+5 = 2. This is your vertex. In the function, your a value will always stay the same as this is your shrink or stretch. In this case, a is 3 so it will go outside the parenthesis. Put that all together and you get the function above.
Hope this helps :)
