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2 years ago

Factor 15c·(a+b)+8·(b+a)

Mathematics

1 answer:

AleksAgata [21]2 years ago

8 0

Answer:

(15c + 8)(a + b).

Step-by-step explanation:

15c·(a+b)+8·(b+a)

(a + b) is common to both parts:

= (15c + 8)(a + b).

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Determine the value of x for which rls if . m2i = 80 - X; and mz2 = 90 - 2x .

Slav-nsk [51]

Answer:

x = 10

Step-by-step explanation:

For the lines to be parallel, the two angles must have the same measure:

80 - x = 90 - 2x

x = 10 . . . . . . . . . add 2x-80

The value of x must be 10 to make the lines parallel.

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3 years ago

an isosceles triangle has congruent sides of 20cm. the base is 10cm. find the height of the triangle.

dolphi86 [110]

Answer:

$\large\boxed{A_\triangle=25\sqrt{15}\ cm^2}$

Step-by-step explanation:

Look at the picture.

The formula of an area of a triangle:

$A_\triangle=\dfrac{bh}{2}$

b - base

h - height

We need a length of a height.

Use the Pythagorean theorem:

$leg^2+leg^2=hypotenuse^2$

We have:

$leg=5,\ leg=h,\ hypotenuse=20$

Substitute:

$5^2+h^2=20^2$

$25+h^2=400$ subtract 25 from both sides

$h^2=375\to h=\sqrt{375}\\\\h=\sqrt{(25)(15)}\\\\h=\sqrt{25}\cdot\sqrt{15}\\\\h=5\sqrt{15}\ cm$

Calculate the area:

$A_\triangle=\dfrac{(10)(5\sqrt{15})}{2}=\dfrac{50\sqrt{15}}{2}=25\sqrt{15}\ cm^2$

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3 years ago

The angles of elevation froma point X to the top of flagpoles A and B are 35* and 45* respectively. If X lies in the middle of t

BartSMP [9]

Let AB = t. And since X lies in the middle, so AX=BX = t/2 .

Let the height of the smaller flagpole is AO and of larger flagpole is BP .

Using tangent ratio rule in each triangle, we will get

$tan 35 =\frac{AO}{t/2} , tan 45= \frac{BP}{t/2} // AO = \frac{t*tan35}{2}, BP=\frac{t*tan45}{2}$

And there ratio is

$\frac{AO}{BP}= \frac{tan 35}{tan 45}=\frac{0.7}{1}$

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Answer:

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Step-by-step explanation:

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Answer:

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