Summer and Winter is the answer
(2x + 10)(x - 9)
2x(x - 9) + 10(x - 9)
2x(x) - 2x(9) + 10(x) - 10(9)
2x² - 18x + 10x - 90
2x² - 8x - 90
The equation given in the question has to be answered to the nearest tenth. The only thing that one should be careful about is the cross multiplication part. Other than that there is no difficulty in the given problem. Now let us get down to the equation in the question.
15/30 = n/34
30 * n = 15 * 34
30n = 510
n = 510/30
= 51/3
= 17
So the value of the unknown variable "n" comes out to be 17.
Answer 3x3.4
Step-by-step explanation:



with that template in mind, let's see,

so, to shift it to the right by 2 units, simply set C = 2.
to stretch it by 2, set A = 1/2.
the smaller A is, the wider it opens, the larger it is, the more it shrinks.