We have that
y = −14x² − 2x − 2
First, we need to transform the equation into its vertex form
(x - h)²=4p(y - k)
<span>Group
terms that contain the same variable
</span>y = (−14x² − 2x )− 2
<span>Factor the
leading coefficient
</span>y = -14*(x² + (2/14)x )− 2
<span>Complete
the square Remember to balance the equation
</span>y = -14*(x² + (2/14)x +(2/28)²-(2/28)²)− 2
y = -14*(x² + (2/14)x +(2/28)²)− 2+14*(2/28)²
y = -14*(x² + (2/14)x +(2/28)²)− 2+56/784
Rewrite as perfect squares
y = -14*(x+(2/28))²− 1512/784------>(x+1/14)²=(-1/14)*(y+1512/784)
4p=-1/14------> p=-1/56
This is a vertical parabola and its focus <span>(h, k + p)</span>
<span>h=-1/14</span>
<span>k+p=(-1512/784)+(-1/56)----> (-1512-14)/784)----> -1526/784</span>
<span>
</span>
<span>the focus is</span>
<span>(-1/14,-1526/784)</span>
Answer:
It will describe the sum of the numbers scanned.
As we can see whatever you scan or take input it will be added to s without any condition. So at the end, sum of all scanned number will be save in variable s
Answer:
The volume would be approximately 2143.573333...
Keeping in mind that an hour is 60 minutes.
When you raise a negative integer (in this case -1) to an even integer (30), the end result will be positive (1), but when you raise it to an odd integer (31), the end result will be negative (-1). The sign of the product fluctuates between positive and negative depending on the type of integer it’s raised to.
