D(S,P) = √(0-0)^2 + √(b-0)^2
d(S,P) = √b^2
d(S,P) = b
so
SP = b
d(P, Q) = √(a-0)^2 + √(b-b)^2
d(P, Q) = √a^2
d(P, Q) = a
so
PQ = a
SQ = c^2 = a^2 + b^2
SQ = √(a^2 + b^2)
answer
the length of one of the diagonals of the rectangle is √(a^2 + b^2)
So what you do is go 5(3y+5)-4y=14 which equals 15y+25-4y=14 which turns into 11y+25=14 than you move the 25 over which equals 11y=-11 so y=-1 then you enter -1 in for y which looks like 5x-4(-1)=14 than you solve that which is 5x+4=14 than you move the 4 over and you get 5x=10 than x=2
x=2
y=-1
Answer:
11
Step-by-step explanation:
If RS=TV
5x-9=2x+3
5x-2x=3+9
3x=12
x=4
RS is 5x-9
5(4)-9
20-9
11
The correct answer is c have a great day
Answer:
Step-by-step explanation:
u2-u1=5.1-3.8=1.3
d=1.3
for that u need to plass 1.3 with all the numbers
7,7 + 1,3=9
9+1.3=10.3
10.3+1.3= 11.6
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