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Vladimir79 [104]
3 years ago
6

You wish to take flying lessons. The introductory course costs $125 per lesson and you want to take 12 lessons. Smith Flying Aca

demy also charged $50 registration fee. You currently have $700 saved for your flying lesson. How much more money do you need to pay for the class in full?
Mathematics
2 answers:
ss7ja [257]3 years ago
4 0

Answer:

$850

Step-by-step explanation:

Multiply the $125 per lesson by 12 and that's $1500. Now add the $50 fee to make it a total of $1550. Subtract $1550 by $700 and you're left with $850 that you still need to pay.

Finger [1]3 years ago
4 0

Answer:

First find the total amount you need to pay.

Since you need $125 for each lesson and you want to take twelve lessons, multiply.

125 * 12 = 1500

Then you need 50 dollars more.

1500 + 50 = 1550

That is the total amount you need to pay for the class.

You have 700 saved up so subtract that from the prices to find the answer.

1550 - 700 = 850.

You need 850 more dollars to pay for the class in full.

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The local branch of the Internal Revenue Service spent an average of 21 minutes helping each of 10 people prepare their tax retu
AURORKA [14]

Answer:

The confidence Interval is [- 0.7053  10.4521]

a: The  hypotheses  are

H0: μ1=μ2    against the claim Ha :μ1≠μ2

b. The critical value for t∝/2 for 17 d.f  t > 2.508 and  t < -2.111

c. t= -2.8422

d. The calculated value of t= -2.8422 is less than t < -2.11 the critical value therefore we reject H0 and conclude there is a difference between the two means.

Step-by-step explanation:

When the standard deviations are not the same then the confidence intervals for mean differences are calculated as

(x1`-x2`)- t∝/2 √s1²/n1 + s2²/n2 < u1-u2 < (x1`-x2`)+ t∝/2 √s1²/n1 + s2²/n2

x1`= 21        x2`= 27

n1=  10       n2= 14

s1= 5.6       s2= 4.3

The degrees of freedom is calculated using

υ = [s₁²/n1 + s₂²/n2]²/ (s₁²/n1 )²/ n1-1 + (s₂²/n2)²/n2-1

= 17

The t∝/2 for 17 d.f = 2.11

Putting the values

(x1`-x2`)- t∝/2 √s1²/n1 + s2²/n2 < u1-u2 < (x1`-x2`)+ t∝/2 √s1²/n1 + s2²/n2

(21-27) - 2.11√5.6²/10+ 4.3²/14 < u1-u2 <(21-27)  +2.11√5.6²/10+4.3²/14

6- 2.11*2.111 < u1-u2 <  ( 6 )  +2.11*2.111

6- 4.4521 < u1-u2 <  ( 6 )  +5.294

- 1.5479 < u1-u2 <  10.4521

The confidence Interval is [- 0.7053  10.4521]

a: The  hypotheses  are

H0: μ1=μ2    against the claim Ha :μ1≠μ2

The claim is that there is a difference in the average time spent by the two services

b. The critical value for t∝/2 for 17 d.f  t > 2.508 and  t < -2.111

The degrees of freedom is calculated using

υ = [s₁²/n1 + s₂²/n2]²/ (s₁²/n1 )²/ n1-1 + (s₂²/n2)²/n2-1

= 17

c. The test statistic is

t= (x1`-x2`)  /√s1²/n1 + s2²/n2

t= (21-27)  /√5.6²/10+ 4.3²/14

t= -6/2.111

t= -2.8422

d. The calculated value of t= -2.8422 is less than t < -2.11 the critical value therefore we reject H0 and conclude there is a difference between the two means.

5 0
3 years ago
Alex is trying to run a certain number of miles by the end of the month Alex is 40% of the way to achieving her goal and she alr
docker41 [41]

Answer:

30 miles

Step-by-step explanation:

Given that:

Alex has some target to run a certain number of miles by the end of the month.

Goal already achieved = 40% of the total goal

Number of miles already run by Alex = 12 miles

To find:

Number of miles that Alex is trying to run by the end of month?

Solution:

We have to find nothing but the goal of Alex here.

Let the number of miles that Alex is trying to run by the end of the month = x miles

As per question statement:

40% of total number of miles to be run = 12 miles

OR

\dfrac{40}{100}\times x = 12\\\Rightarrow 40x=12\times 100\\\Rightarrow x = \dfrac{1200}{40}\\\Rightarrow \bold{x = 30\ miles}

Total number of miles that Alex is trying to run by the end of the month = <em>30 miles</em>

4 0
3 years ago
5) You and a friend live 4 miles apart. You hear the sound of thunder 18 seconds before your friend hears it. Assuming sound tra
Leokris [45]

Answer:

  see attached

Step-by-step explanation:

At 1100 ft per second for 18 seconds, the sound travels 19,800 ft, or 3.75 miles farther to my friend's house. The set of points that lie 3.75 miles farther from my friend's house than from my house form a hyperbolic curve. This is illustrated by the blue line in the attached graph. (My house is the red dot on the left; my friend's house is the red dot on the right.)

The lightning occurred somewhere on the blue curve.

___

If the lightning occurred on the line between our houses, it was 1/8 mile from my house and 3 7/8 mile from my friend's house. (That's close!)

_____

The formula for the curve in the graph is the distance formula applied to the set of points (x, y). It equates the difference of distance from the two houses to 3.75 miles. If one were to write the equation of the hyperbola in standard form, the equation would look a little different and a restriction would need to be applied so the formula would describe only one branch of the hyperbola.

3 0
2 years ago
Add the decimals represented by the models below.
Bad White [126]

Answer:

im sorry cant help

Step-by-step explanation:

8 0
2 years ago
A right angle triangle is shown with hypotenuse equal to 13 centimeters. An acute angle of the triangle is labeled as x degrees.
erastova [34]
Sin = opposite/hypotenuse

so sin (x) = 12/13

answer is 12/13
7 0
3 years ago
Read 2 more answers
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