Answer:
P ( 5 < X < 10 ) = 1
Step-by-step explanation:
Given:-
- Sample size n = 49
- The sample mean u = 8.0 mins
- The sample standard deviation s = 1.3 mins
Find:-
Find the probability that the average time waiting in line for these customers is between 5 and 10 minutes.
Solution:-
- We will assume that the random variable follows a normal distribution with, then its given that the sample also exhibits normality. The population distribution can be expressed as:
X ~ N ( u , s /√n )
Where
s /√n = 1.3 / √49 = 0.2143
- The required probability is P ( 5 < X < 10 ) minutes. The standardized values are:
P ( 5 < X < 10 ) = P ( (5 - 8) / 0.2143 < Z < (10-8) / 0.2143 )
= P ( -14.93 < Z < 8.4 )
- Using standard Z-table we have:
P ( 5 < X < 10 ) = P ( -14.93 < Z < 8.4 ) = 1
Answer:
y = -1/2x +6
Step-by-step explanation:
We can use the slope intercept form of a line
y = mx+b where m is the slope and b is the y intercept
y = -1/2x +b
Substitute the point into the equation
9 = -1/2 (-6) +b
9 = 3+b
9-3 =b
6 =b
y = -1/2x +6
Answer:
(3x5 - 10) • (10x5 + 3)
Step-by-step explanation:
Answer:
2, 1, 1/2, 1/4
Step-by-step explanation:
2¹ = 2
2^0 = 1
2^-¹
= 1/2¹
= 1/2
2^-2
= 1/2²
= 1/2*2
= 1/4
To complete the table
2² 2¹ 2^0 2^-1 2^-2
4 2 1 1/2 1/4
It's the same as adding 2 fractions the product of 2 rational numbers is rational
