The equation of the plane that goes through these points is:
6x + 2y + z = 10.
<h3>How to find the equation of a plane given three points?</h3>
The equation of the plane is found replacing the points into the following equation:
ax + by + c = z.
For point A, we have that:
3b + c = 4.
For point B, we have that:
a + 2b + c = 0.
For point C, we have that:
-a + 6b + c = 4.
Hence the system is:
From the first equation, we have that:
c = 4 - 3b.
Replacing in the second, we have that:
a + 2b + 4 - 3b = 0
a - b = -4.
Replacing in the third, we have that:
-a + 6b + 4 - 3b = 4.
-a + 3b = 0.
a = 3b.
We have that a - b = -4, hence:
3b - b = -4
2b = -4
b = -2.
a = 3b, hence a = -6.
c = 4 - 3b -> c = 10.
Hence the equation is:
ax + by + c = z.
z = -6x - 2y + 10
6x + 2y + z = 10.
More can be learned about the equation of a plane at brainly.com/question/13854649
#SPJ1
Answer:
Option (2)
Step-by-step explanation:
ΔDEF is a dilation image of ΔABC.
Rule for the dilation,
Scale factor = 
= 
= 
= 
Therefore, scale factor by which ΔABC is dilated is .
Option (2) will be the correct option.
Answer:
x₁ = 0
x₂ = 6
Step-by-step explanation:
9x² - 54x = 0
9x(x - 6) = 0
x(x - 6) = 0
x = 0
x - 6 = 0 → x = 6
Hope this helps! :)
Answer:
Y=-1/4X-6
Step-by-step explanation:
y=--1/4X-6
