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Scrat [10]
3 years ago
11

Write the word sentence as an inequality: a number b is at least -3

Mathematics
1 answer:
alekssr [168]3 years ago
7 0
b > 3
_

Pretend that the line is right below the greater than sign.
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How many cubes with side lengths of \dfrac14\text{ cm}
bogdanovich [222]

Answer:

Step-by-step explanation:

Correct question

How many cubes with side lengths of ¼cm needed to fill the prism of volume 4 cubic units?

We know that,

Volume of a cube is s³

V = s³

Where 's' is length of side of a cube

Given that

The cube has a length of ¼cm, and a cube has equal length

s= ¼cm

Then, it's volume is

V = s³

V = (¼)³ = ¼ × ¼ × ¼

V = 1 / 64 cubic unit

V = 0.015625 cubic unit

Then, given that the volume of the prism to be filled is 4 cubic unit

Then,

As, we have to find the number if cubes so we will divide volume of prism by volume of one cube

Then,

n = Volume of prism / Volume of cube

n = 4 / 0.015625

n = 256

So, then required cubes to filled the prism is 256 cubes.

5 0
3 years ago
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He is 187cm tall how many metres is this
k0ka [10]
He is one meter and 87 centimeters tall. 
6 0
3 years ago
The pet store sells bags of pet food. There are four bags of cat food. 1/6 of the bags of food are cat food. How many bags of pe
nikklg [1K]
If 1/6 of the bags of pet food are cat food, then the other 5/6 is other pet food.
Since there are 4 bags that make up 1/6 of the food, multiplying 4 by 6 should get the answer. 4 x 6 = 24
6 0
3 years ago
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In Janie's homeroom 54% of the students' families own a dog and 32% own a dog and a cat. What is the probability that a student'
pogonyaev

Answer:

51,111%

Step-by-step explanation:

We know that 45% have a dog but no cat.  While 23% have both a dog and a cat.

Then Pr(X has cat|X has dog) = Pr(X has dog and cat)/Pr(X has dog)

= Pr(X has dog and cat)/Pr(X has dog) = 0.23/0.45 = 0.51 ≈ 51,111%

The probability that a student’s family owns a cat if the family owns a dog is 51,111%

6 0
3 years ago
If you choose a card at random from a well shuffled deck of 52 cards, what is the probability that the card chosen is not a hear
Vinvika [58]
Sample space ={13 H + 13 D + 13 S + 13 C} = 52 cards

P(getting one heart) = 13/52 = 1/4
P( getting NO heart) = 1-1/4 = 3/4 = 0.75
4 0
3 years ago
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