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ExtremeBDS [4]
3 years ago
12

PLS HELP ASAP!!!! Determine whether each relation is a function. Explain your reasoning.

Mathematics
1 answer:
V125BC [204]3 years ago
6 0
Each domain needs to have one range every x can only have 1 y they can be the same y value so...

Yes it is a function
You might be interested in
What is the period of y=3cot(4x−3π)
Stells [14]
Hello!

hint: we can rewrite your function as below:

<span>3/<span>tan<span>(<span>4x−3π</span>) = </span></span></span>3(1+tan4xtan3π)/tan4x−tan3π = 

=<span>3/<span>tan<span>(<span>4x</span>) = </span></span></span>3cot<span>(<span>4x</span><span>)

</span></span>now, since the period P of cotangent function is pi, then the period of cot(4x), which is the period of our original function, is such that:

<span>"4P=π"


Hope this Helps! Have A Wonderful Day! :)</span>
4 0
3 years ago
A tank contains 9,000 L of brine with 18 kg of dissolved salt. Pure water enters the tank at a rate of 90 L/min. The solution is
aev [14]

Let <em>x(t)</em> denote the amount of salt (in kg) in the tank at time <em>t</em>. The tank starts with 18 kg of salt, so <em>x</em> (0) = 18.

The solution is drained from the tank at a rate of 90 L/min, so that the amount of salt in the tank changes according to the differential equation

d<em>x(t)</em>/d<em>t</em> = - (<em>x(t)</em> kg)/(9000 L) × (90 L/min) = -1/100 <em>x(t)</em> kg/min

or, more succintly,

<em>x'</em> = -1/100 <em>x</em>

This equation is separable as

d<em>x</em>/<em>x</em> = -1/100 d<em>t</em>

Integrating both sides gives

∫ d<em>x</em>/<em>x</em> = -1/100 ∫ d<em>t</em>

ln|<em>x</em>| = -1/100 <em>t</em> + <em>C</em>

<em>x</em> = exp(-1/100 <em>t</em> + <em>C </em>)

<em>x</em> = <em>C</em> exp(-<em>t</em>/100)

(a) Using the initial condition <em>x</em> (0) = 18, we find

18 = <em>C</em> exp(0)   ==>   <em>C</em> = 18

so that

<em>x(t)</em> = 18 exp(-<em>t</em>/100)

(b) After 20 minutes, we have

<em>x</em> (20) = 18 exp(-20/100) = 18 exp(-1/5) ≈ 14.74

so the tank contains approximately 14.74 kg of salt after this time.

7 0
3 years ago
How do you add vectors? Add the vector &lt;3,4&gt; to the vector that goes 7 units at an angle of 2π/3.
telo118 [61]

The sum of two vectors is (- 0.5, 10.1)

<u>Explanation:</u>

To add two vectors, add the corresponding components.

Let u =⟨u1,u2⟩ and v =⟨v1,v2⟩ be two vectors.

Then, the sum of u and v is the vector

u +v =⟨u1+v1, u2+v2⟩

(b)

Two vectors = ( 3, 4 )

angle 2π/3 = 120°

In x axis, the vector is = 7 cos 120°

                                    = 7 X -\frac{1}{2} \\\\=- \frac{7}{2}

In y axis, the vector is = 7 sin 120°

                                   = 7 X 0.866

                                   = 6.062

The second vectors are ( -3.5, 6.062)

Sum of two vectors = [( 3 + (-3.5) ), (4 + 6.062)]

                               = (- 0.5, 10.1)

8 0
3 years ago
total number of boys and girls in a class is 42. if the number of girls is 10 more than the boys find the number of boys?? answe
dsp73

Answer:

\boxed{\sf Total \ number \ of \ boys = 16}

Given:

Total number of boys and girls in class = 42

Total number of girls = 10 more than the boys

To Find:

Total number of boys

Step-by-step explanation:

Let total number of boys be 'x'

\sf So, \\ \sf Total \: number \ of \ girls = x + 10 \\  \\  \therefore \\  \sf \implies    Total \: number \: of \: boys \: and \: girls  \\  \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: = Total \: number \: of \: boys + Total \\  \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  number \: of \: girls \\  \\  \sf \implies 42 = x + (x + 10) \\  \\  \sf 42 = x + (x + 10) \: is \: equivalent \: to \: x + (x + 10)  = 42 : \\  \sf \implies x + (x + 10 )= 42 \\  \sf \implies x + x + 10 = 42 \\  \\  \sf x + x = 2x :  \\  \sf  \implies \boxed{ \sf 2x} + 10 = 42

\sf Substrate \: 10 \: from \: both \: sides :   \\  \sf \implies 2x + (10 -  \boxed{ \sf 10}) = 42 -  \boxed{ \sf 10} \\  \\  \sf 10 - 10 = 0 :  \\  \sf \implies 2x = 42 - 10 \\  \\  \sf 42 - 10 = 32 :  \\  \sf \implies 2x =  \boxed{ \sf 32} \\  \\  \sf Divide \: both \ sides \: by \: 2 :  \\  \sf \implies \frac{2x}{ \boxed{ \sf 2}}  =  \frac{32}{ \boxed{ \sf 2}}  \\  \\  \sf \frac{2x}{2}  =  \frac{ \cancel{2}}{ \cancel{2}}  \times (x) = x :  \\  \sf \implies x =  \frac{32}{2}  \\  \\  \sf  \frac{32}{2}  =  \frac{16 \times  \cancel{2}}{ \cancel{2}}  = 16 :  \\  \sf \implies x = 16

So,

Total number of boys = x = 16

6 0
4 years ago
9-<br><br><br> pls help!!!!<br><br><br><br> math<br><br> -
Andre45 [30]

Answer:

B

Step-by-step explanation:

7 cuz I did this on my notebook

I hope it helps :)

have a greatday

4 0
3 years ago
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