I don't know how to do this problem
1 answer:
You might be interested in
Answer:
51%
Step-by-step explanation:
Given P(passing math) = 59%, P(passing physics) = 26%, and P(passing both) = 17%, you want to find the probability of passing only one of the courses.
<h3>Probability relations</h3>We can record the given probabilities in a 2-way table (values shown in blue). The table is completed by making sure the totals add up (values shown in black).
The probability of passing one course and failing the other is the sum of the probabilities with a yellow background:
42% +9% = 51%
The probability of passing one or the other is 51%.
__
<em>Additional comment</em>
We can also get there using the relation ...
P(A+B) = P(A) +P(B) -P(AB)
The union of A and B also includes their overlap:
P(A+B) = P(AB') +P(A'B) +P(AB)
In other words, the probability of interest is ...
P(AB') +P(A'B) = P(A) +P(B) -2×P(AB) = 59% +26% -2(17%)
P(AB') +P(A'B) = 51%
