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andrey2020 [161]

3 years ago

7

BC=4x+2space, B, C, equals, 4, x, plus, 2, \qquad AB = 8x + 8AB=8x+8space, A, B, equals, 8, x, plus, 8, and \qquad AC = 22AC=22s

pace, A, C, equals, 22, Find BCBCB, C.

1 answer:

navik [9.2K]3 years ago

3 0

Point A, B, and C are collinear. Point B is between A and C. BC = x-7, AB = x- 2, and AC = 7. Find x. 5. Point A, B

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The following table gives annual life insurance premiums per $1,000 of face value. Use the table to determine the annual premium

Papessa [141]

The answer would be C !

4 0

3 years ago

Read 2 more answers

Simplify: (n^22)(n^-6)<br> (n^3)^-4

LenKa [72]

Answer:log

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Step-by-step explanation:

5 0

3 years ago

Which sign makes the statement true?<br> 11<br> 20<br> ? 61%<br> ><br> <<br> Submit<br> ASAP

Tcecarenko [31]

11/20 < 61%

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3 0

3 years ago

Suppose the function of h is defined, for all real numbers as follows: (f) x = -3 if x is <) 3 if x is =0 -2 if x is > 0

V125BC [204]

Answer:

See explanation

Step-by-step explanation:

The question is not properly presented; I will answer this with the following similar question.

$h(x) = -\frac{1}{3}x^2 + 4$ --- $x \ne 2$

$h(x) = -4$ --- $x= 2$

Required

$h(-5)\ \&\ h(2)$

<u>Calculating h(-5)</u>

This implies that: x = -5

$-5 \ne 2$

So, we make use of:

$h(x) = -\frac{1}{3}x^2 + 4$

Substitute -5 for x

$h(-5) = -\frac{1}{3} * (-5)^2 + 4$

$h(-5) = -\frac{1}{3} * 25 + 4$

$h(-5) = -\frac{25}{3} + 4$

Take LCM

$h(-5) = \frac{-25+12}{3}$

$h(-5) = -\frac{13}{3}$

<u>Calculating h(2)</u>

This implies that: x = 2

$2 = 2$

So, we make use of:

$h(x) = -4$

Substitute 2 for x

$h(2) = -4$

<em>Use the above explanation to answer your question</em>

3 0

3 years ago

3x^3 - 2y^-6x^2y^2+xy for x=2/3 and y=1/2

Dominik [7]

Answer:

-13

Step-by-step explanation:

3x^3 - 2y^-6x^2y^2+xy

x=2/3 and y=1/2

Solve :

3x^3 - 2y^-6x^2y^2+xy

Put value of x and y in this equation

= 3(2/3)^3 - 2(1/2)^-6(2/3)^2(1/2)^2+(2/3)(1/2)

= -13

4 0

3 years ago