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tankabanditka [31]
3 years ago
14

A foot ball field measures 100m by 72m. A school marks a football field similar in shape to a fullsize football field but only 3

0m long. What is its width?
Mathematics
1 answer:
Anna35 [415]3 years ago
6 0

Answer: 21.6 m

Step-by-step explanation:

Given

A football field measures 100\ m\times 72\ m

If a football field similar in shape to a full size  has a length l=30\ m

The ratio of the length of the original to the small field is the same

Assume the width of the small field is  w

\therefore \dfrac{100}{30}=\dfrac{72}{w}\\\\\Rightarrow w=30\times \dfrac{72}{100}\\\\\Rightarrow w=21.6\ m  

Thus, the width of the field is 21.6 m

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Step-by-step explanation:

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The distribution of speeds on a particular highway has a mean of 60 mph with a standard deviation of 10 mph. The distribution of
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Answer:

a) At least what percentage of cars is traveling between 40 and 80 mph?

75%

b) At least what percentage of cars is traveling between 20 and 100 mph?

93.75%

c) If a sample of 40 cars is selected at random, estimate the number of cars that are traveling between 40 and 80 mph.

30 cars.

Step-by-step explanation:

We apply Chebyshev's Theorem

This states that:

1) At least 3/4 (75%) of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ.

2) At least 8/9 (88.89%) of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ.

3) At least 15/16 (93.75%) of data falls within 4 standard deviations from the mean - between μ - 4σ and μ + 4σ.

From the question, we have:

Mean of 60 mph

Standard deviation of 10 mph.

a) At least what percentage of cars is traveling between 40 and 80 mph?

Applying:

Applying the first rule: At least 3/4 (75%) of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ.

μ – 2σ

60 - 2(10)

60 - 20

= 40 mph

μ + 2σ.

60 + 2(10)

60 + 20

= 80 mph

Hence, at least 75% of cars is traveling between 40 and 80 mph.

b) At least what percentage of cars is traveling between 20 and 100 mph?

At least 15/6 (93.75%) of data falls within 4 standard deviations from the mean - between μ – 4σ and μ + 4σ.

μ – 4σ

60 - 4(10)

60 - 40

= 20 mph

μ + 4σ.

60 + 4(10)

60 + 40

= 100 mph

Hence, at least 93.75% of cars is traveling between 40 and 80 mph.

c) If a sample of 40 cars is selected at random, estimate the number of cars that are traveling between 40 and 80 mph.

Since we know from question a) that

at least 75% of cars is traveling between 40 and 80 mph.

Given a sample of 40 cars:

75% of 40 cars

= 75/100 × 40

= 30 cars.

The number of cars that are traveling between 40 and 80 mph is 30 cars.

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