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2 years ago

15

In the angle of elevation from the tip of the shadow to the top of the tree is 32 degrees, what is the height of the tree to the

the nearest tenth oslf a foot?
-15.6
-40.0
-21.2
-13.2
Ill mark you the brainlest if you let me. Answer now pleaseeeee

1 answer:

LenaWriter [7]2 years ago

3 0

Answer:

it might be -40.0

Step-by-step explanation:

i did the worl

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Suppose a normal distribution has a mean of 62 and a standard deviation of

lutik1710 [3]

Answer:

62.5%

Step-by-step explanation:

(56 - 62) / 4 = -1.5 z score = 0.0668

(64 - 62) / 4 = 0.5 z score = 0.6915

0.6915 - 0.0668 = 0.6247

Rounded this becomes 62.5%

7 0

2 years ago

Determine the value of each expression.<br> i11=

Basile [38]

Answer:

11 * I

Unless you can tell me what I is equal to, I can't give you a number as an answer. Just take what ever I is equal to, an multiply it by 11. If the answer choices are equations rather than numbers, than just say 11 * 1.

If the question comes with any more information, please comment so I can give you a stronger answer.

Hope this helps! :)

-Sophia

7 0

3 years ago

mt. Everest, the highest elevation in aisa is 29,028 feet above sea level. the dead sea, the lowest elevation, is 1,312 feet bel

andre [41]

Answer:

27716

Step-by-step explanation:

27716!

lol

8 0

3 years ago

Read 2 more answers

The inequality x < 9 or x ≥ 14 can be used to represent the hourly wage, x, of each employee at a store. Which are possible v

Elodia [21]

Answer:

$11, $13, $14

Step-by-step explanation:

all of those answers are greater than $9 but less than or equal to $14.

7 0

3 years ago

Suppose the sediment density (g/cm3 ) of a randomly selected specimen from a certain region is known to have a mean of 2.80 and

Irina18 [472]

Answer:

0.918 is the probability that the sample average sediment density is at most 3.00

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 2.80

Standard Deviation, σ = 0.85

Sample size,n = 35

We are given that the distribution of sediment density is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

Standard error due to sampling:

$=\dfrac{\sigma}{\sqrt{n}} = \dfrac{0.85}{\sqrt{35}} = 0.1437$

P(sample average sediment density is at most 3.00)

$P( x \leq 3.00) = P( z \leq \displaystyle\frac{3.00 - 2.80}{0.1437}) = P(z \leq 1.3917)$

Calculation the value from standard normal z table, we have,

$P(x \leq 3.00) = 0.918$

0.918 is the probability that the sample average sediment density is at most 3.00

4 0

3 years ago