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3 years ago

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According to the bronsted-lowry theory of acids and bases, a base is 1. a substance which when dissolved in water yields oh−. 2.

a proton donor. 3. an electron donor. 4. an electron acceptor. 5. a proton acceptor. 013 2.5 poi

1 answer:

Kryger [21]3 years ago

3 0

According to the Bronsted-Lowry theory of acids and bases, a base is <span> 5. a proton acceptor.</span>

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Balance the following skeleton reaction and identify the oxidizing and reducing agents: Include the states of all reactants and

coldgirl [10]

Answer :

a. The oxidizing agent is: $BH_4^-$

b. The reducing agent is: $ClO_3^-$

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

Reducing agent : It is defined as the agent which helps the other substance to reduce and itself gets oxidized. Thus, it will undergo oxidation reaction.

Oxidizing agent : It is defined as the agent which helps the other substance to oxidize and itself gets reduced. Thus, it will undergo reduction reaction.

The given chemical reaction is,

$BH_4^-(aq)+ClO_3^-(aq)\rightarrow H_2BO_3^-(aq)+Cl^-(aq)$

The oxidation-reduction half reaction will be :

Oxidation : $BH_4^-\rightarrow H_2BO_3^-$

Reduction : $ClO_3^-\rightarrow Cl^-$

Now balance oxygen atom on both side.

Oxidation : $BH_4^-\rightarrow H_2BO_3^-+3H_2O$

Reduction : $ClO_3^-+3H_2O\rightarrow Cl^-$

Now balance hydrogen atom on both side.

Oxidation : $BH_4^-+4OH^-\rightarrow H_2BO_3^-+3H_2O$

Reduction : $ClO_3^-+3H_2O\rightarrow Cl^-+6OH^-$

Now balance the charge.

Oxidation : $BH_4^-+4OH^-\rightarrow H_2BO_3^-+3H_2O+4e^-$

Reduction : $ClO_3^-+3H_2O+6e^-\rightarrow Cl^-+6OH^-$

In order to balance the electrons, we multiply the oxidation reaction by 6 and reduction reaction by 4 and then added both equation, we get the balanced redox reaction.

Oxidation : $6BH_4^-+24OH^-\rightarrow 6H_2BO_3^-+18H_2O+24e^-$

Reduction : $4ClO_3^-+12H_2O+24e^-\rightarrow 4Cl^-+24OH^-$

The balanced chemical equation in acidic medium will be,

$6BH_4^-+4ClO_3^-\rightarrow 6H_2BO_3^-+6H_2O+4Cl^-$

$3BH_4^-+2ClO_3^-\rightarrow 3H_2BO_3^-+3H_2O+2Cl^-$

In the redox reaction, $ClO_3^-$ act as oxidizing agent and $BH_4^-$ act as an reducing agent.

7 0

3 years ago

Consider the balanced equation. CuSO4 + Zn ------> ZnSO4 + Cu If 200.0 g of copper(II) sulfate react with an excess of zinc m

Eva8 [605]

Let's break this down. We know from our balanced equation that (in theory) we'll get the same number of moles of copper out of the reaction that we put into it. So we need to find the number of moles of CuSO4 we have in 200.0 grams. Using the molar mass of CuSO4:
200.0 grams CuSO4 * (1 mole CuSO4)/(159.61 grams CuSO4) =
1.253 moles CuSO4
We know that the moles of CuSO4 and Cu are one-to-one, so we should yield the same number of moles of copper. If we multiply by copper's molar mass, we get:
1.253 moles Cu * (63.55 grams Cu)/(1 mole Cu) = 79.63 grams Cu

4 0

4 years ago

Read 2 more answers

What is the Percent yield is 4.65 got copper is produced by 1.87 percent yield is got copper is produced when 1.87 grams of alum

konstantin123 [22]

Answer:

The percent yield is 70.486%

Explanation:

$3CuSO_{4}+2Al\longrightarrow Al_{2}(SO_{4})_{3}+3Cu\\\\Weight\:of\:Al=1.87g\\54g\:of\:Al\:will\:give\:190.5g\:of\:Cu\\$

$1.87g\:of\:Al\:gives=\frac{190.5\times1.87}{54}=6.597g\:of\:Cu\\ \\Weight\:of\:Cu\:obtained=4.65g\\Theoretical\:Yield=6.597g\\Experimental\:Yield=4.65g\\Percent\:Yield=\frac{Experimental\:Yield}{Theoretical\:Yield}\times100=\frac{4.65}{6.597}\times100=70.486\%$

Hence, the percent yield is 70.486%

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4 years ago

Help me asap Like fr i need to turn this whole edjenuity section by 2 40

lana [24]

Answer:

3/6 or 1/2

Explanation:

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3 years ago

Name the type of bond between atoms in ammonia molecule. Give a reason for your answer

Likurg_2 [28]

Answer:

Covalent bonds are formed when electrons are shared between elements that are nonmetals. The ammonium ion, NH+4 , would have covalent bonds because both nitrogen and hydrogen are nonmetals. ... The rest of the bonds all contain electrons from both hydrogen and nitrogen, so they would be considered ordinary covalent bonds.

6 0

3 years ago

Read 2 more answers