<h2>Answer : Seismic Waves.</h2><h2 /><h3>Explanation : </h3><h3>Vibrations that move through the ground carrying the energy released during an earthquake are called seismic waves.</h3>
Seismic waves are waves of energy which usually travels through the Earth's layers, and as a result release the energy during earthquakes, volcanic eruptions, magma movement, large landslides or large man-made explosions. It is mainly measured through a special instrument called as seismometer and the graph obtained is called as seismograph.
Answer:
Δ[NH₃]/Δt = 2/3 ( Δ[H₂]/Δt )
Explanation:
For determining rates as a function of reaction coefficients one should realize that these type problems are <u>always in pairs</u> of reaction components. For the reaction N₂ + 3H₂ => 2NH₃ one can compare ...
Δ[N₂]/Δt ∝ Δ[H₂]/Δt, or
Δ[N₂]/Δt ∝ Δ[NH₃]/Δt, or
Δ[H₂]/Δt ∝ Δ[NH₃]/Δt, but never 3 at a time.
So, set up the relationship of interest ( ammonia rate vs. hydrogen rate)... nitrogen rate is ignored.
Δ[H₂]/Δt ∝ Δ[NH₃]/Δt
Now, 'swap' coefficients of balanced equation and apply to terms given then set term multiples equal ...
N₂ + 3H₂ => 2NH₃ => 2(Δ[H₂]/Δt) = 3(Δ[NH₃]/Δt) => 2/3(Δ[H₂]/Δt) = (Δ[NH₃]/Δt)
NOTE => Comparing rates individually of the component rates in reaction process, the rate of H₂(g) consumption is 3/2 times <u>faster</u> than NH₃(g) production (larger coefficient). So, in order to compose an equivalent mathematical relationship between the two, one must reduce the rate of the H₂(g) by 2/3 in order to equal the rate of NH₃(g) production. Now, given the rate of one of the components as a given, substitute and solve for the unknown.
CAUTION => When Interpreting rate of reaction one should note that the rate expression for an individual reaction component defines 'instantaneous' rate or speed. <u>This means velocity (or, speed) does not have 'signage'</u>. Yes, one may say the rate is higher or lower as time changes but that change is an acceleration or deceleration for one instantaneous velocity to another. Acceleration and Deceleration do have signage but the positional instantaneous velocity (defined by a point in time) does not. Thus is reason for the 'e-choice' answer selection without the signage associated with the expression terms.
When converting Joules to Kilo-joules think like math kilo is 0.1 of 100 so 200 joules would equal 0.2 kilo-joules. Hope this helps ;)
A ABSORBS HEAT.....................
Answer:
The kinetic energy of the two curling stones is 320 J
Explanation:
Given;
mass of the first curling stone, m₁ = 20 kg
velocity of the first curling stone, v₁ = 4 m/s
velocity of the second curling stone, v₂ = - 4m/s
assuming the second curling stone to have equal mass with the first stone = 20 kg
The kinetic energy of the first curling stone is given by;
K.E₁ = ¹/₂m₁v₁²
K.E₁ = ¹/₂(20)(4)²
K.E₁ = 160 J
The kinetic energy of the second stone is given by;
K.E₂ = ¹/₂m₂v₂²
K.E₂ = ¹/₂ (20) (-4)²
K.E₂ = 160 J
Thus, the kinetic energy of the two curling stones is given by;
K.E = K.E₁ + K.E₂
K.E = 160 J + 160 J
K.E = 320 J
Therefore, the kinetic energy of the two curling stones is 320 J
