The formula for the monoprotic acid is taken as HA, reaction with base is as follows;
HA + NaOH ---> NaA + H₂O
Stoichiometry of acid to base is 1:1
At the neutralisation point, number of HA moles = number of base moles
Number of NaOH moles reacted = 0.100M / 1000 mL /L x 30.0 mL = 0.003 mol
Therefore number of HA moles reacted = 0.003 mol
the mass of acid 0.384 g
Therefore molar mass - 0.384 g/ 0.003 mol = 128 g/mol
The ball will float as it’s density is less than the salt water.
Molar mass Cu(OH)₂ = <span>97.561 g/mol
1 mol --------- 97.561 g
? mol ---------- 68 g
moles = 68 * 1 / 97.561
moles = 68 / 97.561
= 0.6969 moles
hope this helps!</span>
