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Svetlanka [38]
3 years ago
13

What is the Percent yield is 4.65 got copper is produced by 1.87 percent yield is got copper is produced when 1.87 grams of alum

inum reacts with excess copper (11) sulfate
Chemistry
1 answer:
konstantin123 [22]3 years ago
7 0

Answer:

The percent yield is 70.486%

Explanation:

3CuSO_{4}+2Al\longrightarrow Al_{2}(SO_{4})_{3}+3Cu\\\\Weight\:of\:Al=1.87g\\54g\:of\:Al\:will\:give\:190.5g\:of\:Cu\\

1.87g\:of\:Al\:gives=\frac{190.5\times1.87}{54}=6.597g\:of\:Cu\\ \\Weight\:of\:Cu\:obtained=4.65g\\Theoretical\:Yield=6.597g\\Experimental\:Yield=4.65g\\Percent\:Yield=\frac{Experimental\:Yield}{Theoretical\:Yield}\times100=\frac{4.65}{6.597}\times100=70.486\%

Hence, the percent yield is 70.486%

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Left Panel

Short answer A

<em><u>Solution</u></em>

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Sodium Phosphate + Calcium Chloride ===> Sodium Chloride + Calcium Phosphate.

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<em><u>Step Two</u></em>

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<em><u>Step Three</u></em>

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<em><u>Step Four</u></em>

Find the number of moles of Ca3(PO4)2 needed.

This requires that you use the balance numbers from the balanced equation.

For every 3 moles of CaCl2 you have, you get 1 mole of Ca3(PO4)2

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Find the molar mass of Ca3(PO4)2

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Molar Mass = 120 + 62 + 128= 310 grams per mole.

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1 mole of Ca3(PO4)2 has a molar mass of 310 gram

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x = 1.13933 moles * 310 grams /mole

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