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Svetlanka [38]
3 years ago
13

What is the Percent yield is 4.65 got copper is produced by 1.87 percent yield is got copper is produced when 1.87 grams of alum

inum reacts with excess copper (11) sulfate
Chemistry
1 answer:
konstantin123 [22]3 years ago
7 0

Answer:

The percent yield is 70.486%

Explanation:

3CuSO_{4}+2Al\longrightarrow Al_{2}(SO_{4})_{3}+3Cu\\\\Weight\:of\:Al=1.87g\\54g\:of\:Al\:will\:give\:190.5g\:of\:Cu\\

1.87g\:of\:Al\:gives=\frac{190.5\times1.87}{54}=6.597g\:of\:Cu\\ \\Weight\:of\:Cu\:obtained=4.65g\\Theoretical\:Yield=6.597g\\Experimental\:Yield=4.65g\\Percent\:Yield=\frac{Experimental\:Yield}{Theoretical\:Yield}\times100=\frac{4.65}{6.597}\times100=70.486\%

Hence, the percent yield is 70.486%

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Light energy (in both visible and invisible forms) is a form of _____ energy.
Ainat [17]

Answer:

D: Electromagnetic

Explanation:

Chemical energy is the energy in chemical bonds which is a type of potential energy, eliminating both B and C. While kinetic energy is the energy of motion, photons are a wave/ particle so thinking it would have kinetic energy wouldn't be your fault but light is on the electromagnetic spectrum making D the most likely answer.

7 0
3 years ago
Read 2 more answers
At 25.0 °C the Henry's Law constant for sulfur hexafluoride (SP) gas in water is 2.4x 10 M/atm Calculate the mass in grams of SF
Dmitry_Shevchenko [17]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The mass is m =  0.0349 \ g

Explanation:

From the question we are told that

   The Henry's Law constant is  k = 2.4 *10^{10} M/atm

   The volume of water is V = 525 \ ml = 0.525 \ L

   The partial pressure is  P =  1.90 \ atm

   The temperature is T  = 25 ^oC

Henry's  law is mathematically represented as

       C  = P * k

Where C is  the concentration of sulfur hexafluoride(SP)

substituting value

        C = 1.90 * 2.4*10^{-4}

        C = 4.56*10^{-4} \ M

The number of moles of  SP is mathematically represented as

        n = C * V

substituting value

       n =  0.525 * 4.56*10^{-4}

       n =  2.39 *10^{-4} \ moles

The mass of SP that dissolved is

          m = n * Z

Where Z is the molar mass of SP which has a constant value of

           Z = 146 g/mole

So

         m =  2.394*10^{-4} * 146

         m =  0.0349 \ g

6 0
3 years ago
100
Margarita [4]

What's your question BTW?

Can't understand what u have typed

7 0
3 years ago
a 1.750-g sample of mercury metal ws combined with 1.394 g of bromine. Determine the empirical formula of the mercury bromide th
Airida [17]

Answer:

HgBr₂.

Explanation:

  • To determine the empirical formula of the mercury bromide that is produced, we should calculate the no. of moles of Hg (1.750 g) and Br (1.394 g) used to prepare the mercury bromide.

no. of moles of Hg = mass/atomic mass = (1.75 g)/(200.59 g/mol) =  0.00872 mol.

no. of moles of Br = mass/atomic mass = (1.394 g)/(79.904 g/mol) =  0.01744 mol.

  • We divide by the lowest no. of moles (0.00872) to get the mole ratio:

The mole ratio of (Br: Hg) is: (2: 1).

<em>So, the empirical formula is: HgBr₂.</em>

<em></em>

6 0
3 years ago
Hello everyone any one free for c h a t​
sleet_krkn [62]

Reply:

Hi! What ch4t? i'd like to know ^^

4 0
2 years ago
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