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Masja [62]
3 years ago
10

The diagram below represents a portion of a cell membrane. The arrow indicates that the cell membrane is carrying out the proces

s of...
​
Chemistry
1 answer:
Llana [10]3 years ago
8 0

Answer:

I'm feeling nice today so heres the answer

Explanation:

In the portion of the cell membrane shown in the diagram, the arrow indicates the process of active transport.

Explanation:

Active transport is one of the mechanisms of transmembrane transport, which involves the use of energy. The diagram (see image) shows the hydrogen (H⁺) output from the cytoplasm to the extracellular space, through an H⁺ pump —consuming ATP— which represents an active transport process.

The hydrophobic nature of the cell membrane prevents the free passage of hydrosoluble elements or ions, as H⁺, so they require the use of active transport to pass through it.

The other options presented are not correct, because

Respiration is a process that occurs in the mitochondria.

Diffusion is a passive transport process that does not require energy.

Cellular recognition depends on membrane proteins that act as specific receptors.

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In a __________ change the identity of the substance is
galben [10]

Answer:

physical - arrangement of molecules changes

chemical - identity changes

Explanation:

7 0
4 years ago
What coefficient will Oy have after balancing this equation?
Gelneren [198K]

la respuesta es la letra C. 8

8 0
3 years ago
Suppose in an experiment to determine the amount of sodium hypochlorite in bleach, 0.0000524 mol K I O 3 were titrated with an u
11111nata11111 [884]

<u>Answer:</u> The amount of sodium thiosulfate required is 2.62\times 10^{-5} moles

<u>Explanation:</u>

Moles of KIO_3 solution given = 0.0000524 moles

The chemical equation for the reaction of potassium iodate and sodium thiosulfate follows:

2KIO_3+Na_2S_2O_3\rightarrow K_2S_2O_3+2NaIO_3

By Stoichiometry of the reaction:

2 moles of potassium iodate reacts with 1 mole of sodium thiosulfate

So, 0.0000524 moles of potassium iodate will react with = \frac{1}{2}\times 0.0000524=0.0000262mol of sodium thiosulfate

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4 0
3 years ago
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3 years ago
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If air has a dry-bulb temperature of 2°C
Allisa [31]

Answer:

The relative humidity is 36%.

Explanation:

Relative humidity is the measure of ratio of actual vapor density to saturated vapor density in a given system. So there are different ways to measure the relative humidity in the atmosphere. One of the common ways is to measure using Psychrometer. In this instrument, two different thermometers are used as measuring device. One of the thermometer measures the humidity in dry air and another in wet air. So the difference of the temperature of dry and wet air bulb will be related to determine the relative humidity percentage. The formula to determine the relative humidity using this method is as below.

Relative humidity=\frac{(e_{w}-[N*(1+0.00115*T_{w}*(T_{d}-T_{w}))])*100}{e_{d} }

Also,

e_{d}=6.112*e^{[\frac{(17.502*T_{d} )}{(240.97+T_{d} )}]}

And,

e_{w}=6.112*e^{[\frac{(17.502*T_{w} )}{(240.97+T_{w} )}]}

Here e =2.718, T_{d} and T_{w} are the temperature at dry bulb and wet bulb temperatures, respectively.

So, the relative humidity after substituting the values of Td = 2 C and Tw = -2 C is 36%.

6 0
3 years ago
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