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2 years ago

I need help with this..?

Mathematics

1 answer:

Slav-nsk [51]2 years ago

4 0

Answer:

just flip the shape upside down

Step-by-step explanation:

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So if there is 575 students and 20% lile salad how many students is it?

Reika [66]

I think you multiply, 575*0.20=115?

4 0

3 years ago

Use the confidence interval to find the estimated margin of error. Then find the sample mean. A biologist reports a confidence i

Pavlova-9 [17]

Answer:

$\bar X = \frac{Lower +Upper}{2}$

$\bar X= \frac{1.9+3.3}{2}= 2.6$

And the margin of error with this one:

$\bar X = \frac{Upper-Lower}{2}$

$ME = \frac{3.3-1.9}{2}= 0.7$

Step-by-step explanation:

Assuming that the parameter of interest is the sample mean $\mu$ . And we can estimate this parameter with a confidence interval given by this formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

For this case the confidence interval is given by (1.9, 3.3)

Since the confidence interval is symmetrical we can estimate the sample mean with this formula:

$\bar X = \frac{Lower +Upper}{2}$

$\bar X= \frac{1.9+3.3}{2}= 2.6$

And the margin of error with this one:

$\bar X = \frac{Upper-Lower}{2}$

$ME = \frac{3.3-1.9}{2}= 0.7$

7 0

3 years ago

Now just 2. Thank you

Levart [38]

The correct choice is B
x is greater than equals to -4.25

8 0

3 years ago

Match the number with its opposite. Match Term Definition 9.2 A) 2.9 −2.9 B) −4.1 −1.4 C) −9.2 4.1 D) 1.4

jenyasd209 [6]

We have these opposite pairs

9.2 and -9.2
2.9 and -2.9
1.4 and -1.4
4.1 and -4.1

So all we're doing is matching each positive number with its negative version. In terms of a visual, the opposite of a number is mirrored over 0 on the number line. So for instance, the opposite of 2 is -2, with each being two units away from 0 on the number line.

8 0

3 years ago

In a research laboratory, a scientist measures the mass of a 1-carat diamond and finds it to be 200 milligrams, measured to the

vlada-n [284]

Answer:

$D=3.5\ gr/cm^3$

Step-by-step explanation:

<u>Density</u>

The density of an object of mass m and volume V is given by

$\displaystyle D=\frac{m}{V}$

It can be expressed in common units like $gr/lt, Kg/m^3, gr/cm^3$ or any other combination of proper mass [M] by volume [V] units.

The data provided in the question is

$m=200\ mg = 0.2\ gr$

$V=0.057\ cm^3$

Thus, the measured density is

$\displaystyle D=\frac{0.2\ gr}{0.057 \ cm^3}$

$\boxed{D=3.5\ gr/cm^3}$

We have expressed the result with 1 decimal place because the mass was measured to the nearest hundred milligrams (or one-tenth grams). Any further decimal is senseless because that precision comes from calculations, not from measurements.

6 0

3 years ago