Step One
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Find the length of FO (see below)
All of the triangles are equilateral triangles. Label the center as O
FO = FE = sqrt(5) + sqrt(2)
Step Two
======
Drop a perpendicular bisector from O to the midpoint of FE. Label the midpoint as J. Find OJ
Sure the Pythagorean Theorem. Remember that OJ is a perpendicular bisector.
FO^2 = FJ^2 + OJ^2
FO = sqrt(5) + sqrt(2)
FJ = 1/2 [(sqrt(5) + sqrt(2)] \
OJ = ??
[Sqrt(5) + sqrt(2)]^2 = [1/2(sqrt(5) + sqrt(2) ] ^2 + OJ^2
5 + 2 + 2*sqrt(10) = [1/4 (5 + 2 + 2*sqrt(10) + OJ^2
7 + 2sqrt(10) = 1/4 (7 + 2sqrt(10)) + OJ^2 Multiply through by 4
28 + 8* sqrt(10) = 7 + 2sqrt(10) + 4 OJ^2 Subtract 7 + 2sqrt From both sides
21 + 6 sqrt(10) = 4OJ^2 Divide both sides by 4
21/4 + 6/4* sqrt(10) = OJ^2
21/4 + 3/2 * sqrt(10) = OJ^2 Take the square root of both sides.
sqrt OJ^2 = sqrt(21/4 + 3/2 sqrt(10) )
OJ = sqrt(21/4 + 3/2 sqrt(10) )
Step three
find h
h = 2 * OJ
h = 2* sqrt(21/4 + 3/2 sqrt(10) ) <<<<<< answer.
Answer:
-8a + 12
Step-by-step explanation:
-2(4a - 6)
-2(4a) - -2(6)
-8a - -12
-8a + 12
Answer:
x= -13/5
Step-by-step explanation:
Answer:
8 cylinders
Step-by-step explanation:
The surface area of a cylinder is given by the formula ...
A = 2πr(r +l) . . . . . for radius r and length l
__
The cylinders Rufus has each have an area of ...
A = 2π(5 cm)(5 cm +4 cm) = 90π cm² ≈ 282.74 cm²
That means 2500 cm² of paint will cover ...
2500 cm²/(282.74 cm²/cylinder) ≈ 8.84 cylinders
Rufus has enough paint to cover 8 cylinders completely.
Answer:
80 questions
Step-by-step explanation:
- 35/100 = 28/x
- 35x = 28(100)
- 35x = 2800
- x = 2800/35
- x = 80
