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3 years ago

Which is the dependent variable in 4x^2-5/6x-9=y if y=f(x)

Mathematics

1 answer:

olga55 [171]3 years ago

4 0

Answer:

Step-by-step explanation:

The expression

y = f(x)

tells you that y is the dependent variable, and that it depends on x, the independent variable. The <em>independent</em> variable is always the function argument. Any variable that depends on that is the <em>dependent</em> variable.

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PWEASE HELP ME THIS IS SO HARD!

umka2103 [35]

Answer:

The answer is C

Step-by-step explanation:

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3 years ago

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2 400 000 in standard form

Archy [21]

It's going to be 2.4 * 10 to the power of 6.

Hope this helped =)

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3 years ago

Which pair of functions have the same domain? A. F(x)= sin x and g(x) = tan x B. F(x) = cos x and f(x) = csc x C. G(x) = tan x a

EastWind [94]

Answer:

The correct choice is D

Step-by-step explanation:

The trigonometric functions, $\sin x$ and $\cos x$ are defined for all real numbers.

$\tan x=\frac{\sin x}{\cos (x)}$ , this function is not defined where $\cos x=0$ .

$\cot x=\frac{\cos x}{\sin (x)}$ , this function is not defined where $\sin x=0$ .

$\csc x=\frac{1}{\sin (x)}$ , this function is not defined where $\sin x=0$ .

For option A

The domain of $f(x)=\sin(x)$ is all real numbers.

The domain of g(x) =tanx is $x\ne \frac{(2n+1)\pi}{2}$

For option B

The domain of $f(x)=\cos(x)$ is all real numbers.

The domain of f(x) =csc(x) is $x\ne n\pi$

For option C,

The domain of G(x) =tanx is $x\ne \frac{(2n+1)\pi}{2}$

The domain of f(x) =cot(x) is $x\ne n\pi$

For option D;

The domain of f(x) =cot(x) is $x\ne n\pi$

The domain of f(x) =csc(x) is $x\ne n\pi$

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3 years ago

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WILL GIVE BRAINLIEST!

Natali [406]

So you’d add 5 and 3 so it’s 8 ft/s

You then divide 220/8

So it should be 27.5 seconds.

Sorry about that other guy. Hope this helps!

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3 years ago

Find the volume of the solid under the surface z = 5x + 9y 2 and above the region bounded by x = y 2 and x = y 3.

Yanka [14]

Call the region in the $x$ - $y$ plane, bounded by $x=y^2$ and $x=y^3$ , $\mathcal D$ . Then the volume under the given surface is

$\displaystyle\iint_{\mathcal D}(5x+9y)\,\mathrm dA=\int_{y=0}^{y=1}\int_{x=y^3}^{x=y^2}(5x+9y)\,\mathrm dx\,\mathrm dy=\frac{83}{140}$

8 0

3 years ago