Answer:
4th graph
6th graph
3rd graph
Step-by-step explanation:
Linear = y = x + 3
it is 4th graph
when you substitute x = 0 y is 3
and when y = 0 x is -3
Quadratic = y = 3x^2
It is 6th graph
for both positive and negative values of x, y is rapidly increasing
Exponential = y = 3^x
it is 3rd graph
for x = 0 y value is 1 because 3^0 = 1
for positive values of x, y is exponentially rising
for negative values of x it is nearly almost touches zero
144 degrees, q=s, so 3a=4a-12. a=12, and 12*12= 144
Answer: D) 10
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Explanation:
I'm assuming points M and N are midpoints of segments FD and FE respectively. If that's the case, then segment DE is twice as long compared to segment MN. We consider MN to be a midsegment.
So,
DE = 2*(MN)
3x-2 = 2*(x+4)
3x-2 = 2x+8
3x-2x = 8+2
x = 10
You would need to isolate the "X" variable because it is common in all 3 equations.
