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MArishka [77]
3 years ago
9

Part A picture above

Mathematics
1 answer:
-BARSIC- [3]3 years ago
8 0

Answer:

<em>Part A </em>C = (10,5)<em>  Part B </em>C. D'(0,10)

Step-by-step explanation:

<em>Part A</em>

Since c is at the point (2,1) in relation to the origin, we can multiply those distances by our scale factor of 5

(2,1) * 5 = (10,5)

The new point C is going to be (10,5)

<em>Part B</em>

If you dilate with a factor of 5 -- relative to the origin -- you have to multiply the distance from <em>the origin</em> by 5.

In this case, point D is already on the y axis, so it's x value wouldn't be affected. Point D is currently 2 units away from (0,0), so we can multiply 2*5 to get 10 -- our ending point is (0,10)

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Step-by-step explanation:

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2 years ago
How do i solve for x if 6x - 6 - 7x =6
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Answer:

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Step-by-step explanation:

Step  1  :

Pulling out like terms :

1.1     Pull out like factors :

  -x - 12  =   -1 • (x + 12)

Equation at the end of step  1  :

Step  2  :

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Answer the question circled and if you want to, the questions below
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4^3 is 64 and 3^4 is 81. Therefore the answer to the circled question is -17.
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Solve 7x2(x + 1) = 6x + 14<br> Ox=-12<br> Ox = 12<br> Ox= -16<br> Ox = 16
Evgen [1.6K]

\large\displaystyle\text{$\begin{gathered}\sf 7x-2(x+1)=6x+4 \end{gathered}$}

Use the distributive property to multiply −2 by x+1.

  • \large\displaystyle\text{$\begin{gathered}\sf 7x-2x-2=6x+14 \end{gathered}$}

Combine 7x and −2x to get 5x.

  • \large\displaystyle\text{$\begin{gathered}\sf 5x-2=6x+14 \end{gathered}$}

Subtract 6x on both sides.

  • \large\displaystyle\text{$\begin{gathered}\sf 5x-2-6x=14 \end{gathered}$}

Combine 5x and −6x to get −x.

  • \large\displaystyle\text{$\begin{gathered}\sf -x-2=14 \end{gathered}$}

Add 2 to both sides.

  • \large\displaystyle\text{$\begin{gathered}\sf -x=14+2 \end{gathered}$}

Add 14 and 2 to get 16.

  • \large\displaystyle\text{$\begin{gathered}\sf -x=16 \end{gathered}$}

Multiply both sides by −1.

  • \large\displaystyle\text{$\begin{gathered}\sf x=-16 \ \ \to \ \ \ Answer \end{gathered}$}

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