1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
iren [92.7K]
3 years ago
13

What is the sum of -2 and -7

Mathematics
2 answers:
shutvik [7]3 years ago
8 0

Answer: -9

Step-by-step explanation:

Serga [27]3 years ago
6 0

-2-7 is equal to -9

hope this helps

You might be interested in
and are independent Gaussian (Normal) random Variables. has mean 13.9 and variance 5.2; has mean 6.9 and variance 3.8. . (a) Cal
omeli [17]

This question is incomplete, the complete question is;

X and Y are independent Gaussian (Normal) random Variables. X has mean 13.9 and variance 5.2; Y has mean 6.9 and variance 3.8. . (a) Calculate P( W> 10)

Answer:

P( W> 10) is 0.1587

Step-by-step explanation:

Given that;

X ⇒ N( 13.9, 5.2 )

Y ⇒ N( 6.9, 3.8 )

W = X - Y

Therefore

E(W) = E(X) - E(Y)

= 13.9 - 6.9 = 7

Var(W) = Var(X) + Var(Y) -2COV(X.Y)

[ COV(X,Y) = 0 because they are independent]

Var(W) = 5.2 + 3.8 + 0

= 9

Therefore

W ⇒ N( 7, 9 )

so

P( W > 10 )

= 1 - P( W ≤ 10 )

= 1 - P( W-7 /3   ≤   10-7 /3 )

= 1 - P( Z ≤ 1 )           [ Z = W-7 / 3 ⇒ N(0, 1)  ]

from Standard normal distribution table, P( Z ≤ 1 )  = 0.8413

so

1 - P( Z ≤ 1 )  = 1 - 0.8413 = 0.1587

Therefore P( W> 10) is 0.1587

8 0
3 years ago
Please help me this is due today at 11:59
k0ka [10]

Answer:

NM corresponds with DC, and the scale factor is 3

7 0
2 years ago
For party decorations, you buy 6 rolls of crepe paper and 20 balloons for $11.90. After you start decorating, you determine that
Morgarella [4.7K]

Answer:

Find out the  how much did each roll of crepe paper cost .

To prove

Let us assume that the cost of the  roll of crepe paper be x.

Let us assume that the cost of the balloon be y .

As given

For party decorations, you buy 6 rolls of crepe paper and 20 balloons for $11.90.

Than the equation becomes

6x + 20y = 11.90

As given

After you start decorating, you determine that you need more party decorations.

You buy 2 more rolls of crepe paper and 15 more balloons for $6.05.

Than the equation becomes

2x + 15y = 6.05

Than two equations are

6x + 20y = 11.90 and 2x + 15y = 6.05

Multiply 2x + 15y = 6.05 by 3 and subracted with 6x + 20y = 11.90

6x - 6x + 45y -20y = 18.15 - 11.90

25y = 6.25

y = \frac{6.25}{25}

y = $0.25

Put in the equation 2x + 15y = 6.05

2x + 15 × 0.25 = 6.05

2x = 6.05 - 3.75

2x = 2.3

x = \frac{2.3}{2}

x = $1.15

Therefore the each roll of crepe paper cost is  $1.15 .

6 0
3 years ago
Read 2 more answers
Which list shows these numbers In order from least to greatest?​
garik1379 [7]

Answer:

2,4,3,1

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Write -33/12 as a mixed number in reduced form. -2 -1 -2 -2
AysviL [449]
-33/12. Lets forget the negative symbol.

12 goes into 33, 2 times with 9 remaining.

So now get the negative sign back.

It will be -2 9/12 but you can reduce that to -2 3/4.

Hope this helps :)
7 0
3 years ago
Other questions:
  • A triangle is placed in a semicircle with a radius of 3 yd, as shown below. Find the area of the shaded region.
    11·1 answer
  • Simplify the following expression.
    13·1 answer
  • Please help. Show work, THANK you so much!
    10·1 answer
  • What is the value of x in the equation 6x − 22 = 76?
    5·2 answers
  • What is the solution to the linear equation?
    8·1 answer
  • Which graph shows a function whose inverse is also a function?
    11·1 answer
  • When Dylan checks their school lunch account, the
    10·1 answer
  • What is LCM of 24,30,36?<br> in a long method ​
    12·1 answer
  • PLS HELP I WILL GIVE 50 POINTS!
    8·1 answer
  • Explain how James Fenimore Cooper’s works connected the fine arts with changes in the American way of life.
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!