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iren [92.7K]
3 years ago
13

What is the sum of -2 and -7

Mathematics
2 answers:
shutvik [7]3 years ago
8 0

Answer: -9

Step-by-step explanation:

Serga [27]3 years ago
6 0

-2-7 is equal to -9

hope this helps

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Please help me please help me please help me please help me please help me please help me please​
Serga [27]

Answer:

first one is square root

don't know the second tho

4 0
2 years ago
12 ft<br> 8 ft<br> 8 ft<br> Find the area of the kite.
mamaluj [8]
I’m not sure but I’m guessing it could be 8 ft
4 0
3 years ago
Read 2 more answers
Determine if the statement is always, sometimes or never true. There are 300 degrees in the sum of the interior angles of a poly
Marrrta [24]

Answer:

Never

Step-by-step explanation:

Using the formula to find the sum of the interior angles, (n-2) * 180, we can work backwards.

300/180 +2 = 11/3 or 3.666. Polygons cannot have decimal sides therefore your answer is never.

6 0
3 years ago
If a triangle has an area of 192 mm2, and the
Debora [2.8K]

Answer:32mm

Step-by-step explanation:

area of triangle = 1/2 *base * height

192mm2 = 1/2 *b* 12mm

192 =6b

base=192/6

base= 32mm

3 0
3 years ago
A rock is thrown upward with an initial velocity of 16 ft/s from an initial height of 5 ft. How much time does it take for the r
Bogdan [553]
Check the picture below.

so it hits the ground when y = 0, thus

\bf ~~~~~~\textit{initial velocity}\\\\&#10;\begin{array}{llll}&#10;~~~~~~\textit{in feet}\\\\&#10;h(t) = -16t^2+v_ot+h_o&#10;\end{array} &#10;\quad &#10;\begin{cases}&#10;v_o=\stackrel{16}{\textit{initial velocity of the object}}\\\\&#10;h_o=\stackrel{5}{\textit{initial height of the object}}\\\\&#10;h=\stackrel{}{\textit{height of the object at "t" seconds}}&#10;\end{cases}

\bf h(t)=-16t^2+16t+5\implies \stackrel{h(t)}{0}=-16t^2+16t+5&#10;\\\\\\&#10;16t^2-16t-5=0\implies (4t+1)(4t-5)=0\\\\&#10;-------------------------------\\\\&#10;4t+1=0\implies 4t=-1\implies t=-\cfrac{1}{4}\\\\&#10;-------------------------------\\\\&#10;4t-5=0\implies 4t=5\implies t=\cfrac{5}{4}\implies \boxed{t=1\frac{1}{4}}

since "t" is seconds it took, it can't be a negative amount.

5 0
3 years ago
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