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I am Lyosha [343]
3 years ago
7

Five times the difference between negative seven and the quotient of -42 and -6

Mathematics
1 answer:
inn [45]3 years ago
7 0
The quotient of -42 and -6 (-42/-6) is -7-7=-14  -14 times 5 =-70 so your answer should be -70
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Al sumar fracciones con igual denominador, debemos sumar numerador con numerador y denominador con denominador. Verdadero o fals
Ahat [919]

Answer:

La respuesta es falso.  

Step-by-step explanation:

La respuesta es falso.  

Cuando se suman fraccciones con igual denominador, se suman los numeradores (numerador con numerador) y se deja el mismo denominador (el cual es común en ambos). Por ejemplo, la suma de 1/5 + 3/5 da como resultado:    

\frac{1}{5} + \frac{3}{5} = \frac{1 + 3}{5} = \frac{4}{5}

En el caso de fracciones con diferentes denominadores, tampoco se suma numerador con numerador y denominador con denominador. En ese caso se debe encontrar el mínimo común múltiplo.

 

Por lo tanto, la respuesta es falso.

Espero que te sea de utilidad!

7 0
2 years ago
What is 3/4 as a percentage
luda_lava [24]

Answer:

75%

Step-by-step explanation:

A percent is a value out of 100.

Change the fraction \frac{3}{4} to an equivalent fraction with the denominator equal to 100.

\frac{3}{4} × \frac{25}{25} = \frac{75}{100}

This fraction represents a percent.

\frac{75}{100} = 75%

5 0
2 years ago
Please help! ill give brainliest!
prohojiy [21]
B

Step by step equation
7 0
3 years ago
70
BaLLatris [955]

Answer:

160 is the answer please tell me if im wrong

5 0
2 years ago
Match the width with the given area and length of a rectangle.
torisob [31]

Answer:

5 cm A = 44cm; <u>w</u><u> </u><u>=</u><u> </u><u>8</u><u>.</u><u>8</u><u> </u><u>cm</u>

7.5 cm A = 48.75 cm2; <u>w</u><u> </u><u>=</u><u> </u><u>6.5</u><u> </u><u>cm</u>

5 cm A = 31.25; <u>w</u><u> </u><u>=</u><u> </u><u>6</u><u>.</u><u>2</u><u>5</u>

9.25 cm A = 55.5 cm; <u>w</u><u> </u><u>=</u><u> </u><u>6</u><u> </u><u>cm</u>

Step-by-step explanation:

What you have to do to find the answer is to take the length which for the first problem is 5 cm and then multiply the 5 by each width until you get the area. Example; Length <em>x</em> Width = Area

Basically you use the length times all of the widths until you match up the area.

Hope I could help

3 0
3 years ago
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