4800 divide by 3=1600 (2 cars 1 truck)
4600-1600-3000 (6 cars)
3000 divide by 3 = 1000(2cars)
1000 times 2=2000(4 cars )
4800-2000-2800 (2 cars 3 trucks)
$2,800 is your answer
Answer:
11.7 in
Step-by-step explanation:
1/3 ln(<em>x</em>) + ln(2) - ln(3) = 3
Recall that
, so
ln(<em>x</em> ¹ʹ³) + ln(2) - ln(3) = 3
Condense the left side by using sum and difference properties of logarithms:


Then
ln(2/3 <em>x</em> ¹ʹ³) = 3
Take the exponential of both sides; that is, write both sides as powers of the constant <em>e</em>. (I'm using exp(<em>x</em>) = <em>e</em> ˣ so I can write it all in one line.)
exp(ln(2/3 <em>x</em> ¹ʹ³)) = exp(3)
Now exp(ln(<em>x</em>)) = <em>x </em>for all <em>x</em>, so this simplifies to
2/3 <em>x</em> ¹ʹ³ = exp(3)
Now solve for <em>x</em>. Multiply both sides by 3/2 :
3/2 × 2/3 <em>x</em> ¹ʹ³ = 3/2 exp(3)
<em>x</em> ¹ʹ³ = 3/2 exp(3)
Raise both sides to the power of 3:
(<em>x</em> ¹ʹ³)³ = (3/2 exp(3))³
<em>x</em> = 3³/2³ exp(3×3)
<em>x</em> = 27/8 exp(9)
which is the same as
<em>x</em> = 27/8 <em>e</em> ⁹
Here are the answer: a) R = 3.6 and b) A = 2
Step-by-step explanation:
Given,
R is inversely proportional to A.
R ∝ 
so, R =
-------eq 1 where k is any constant
To find the values of a) R when A = 5 and
b) Value of A when R = 9
Now,
Putting R = 12 and A = 1.5 in eq 1 we get,
12 = 
or, k = 12×1.5 = 18
From eq 1 we get,
R =
--------- eq 2
Now,
a) Putting A= 5 in eq 2 we get,
R =
= 3.6
b) Putting R = 9 in eq 2 we get
R =
or, A =
= 2