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Solnce55 [7]
3 years ago
12

What if angle 6=50 then find angle 11 what would it be how would you do it

Mathematics
1 answer:
Mars2501 [29]3 years ago
3 0
Is there a graph for this problem?
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Find the unknown 8/28 = m/7
vredina [299]
The answer to the question is m = 2
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Please help I will give out brainliest I have done the first one already.
pentagon [3]

Answer:

In drawing an elevation drawing, there are four or five views of the sides of an object which may be displayed including the front, rear,  and sides of the object

The elevation drawing is a scaled horizontal orthographic projection showing one side of an object to  a plane vertical parallel to the object's sides so as to depict the appearance of the completed object appearance

The required elevation is included in the attached diagram

Step-by-step explanation:

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Identify the equation in slope-intercept form for the line containing the point (-4,1) and (2,3)
oksano4ka [1.4K]

Answer:

The point slope formula is

(y−y1)=m(x−x1)

Where m = the slope calculated as y2−y1x2−x1

(x1,y1)(x2,y2)

(-4 , 1) (-2 , 3)

Solve for the slope

m = 3−1−2−(−3) = 21 = m = 2

(y−3)=2(x−(−2)) Plug in known values.

y−3=2(x+2) Simplify signs

y−3=2x+4 Use Distributive property

y=−2x+4+3 isolate the y variable

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3 years ago
Which equation is a linear function?<br> Please answer within 5 minutes
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Answer:

y= x/2-5

Step-by-step explanation:

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2 years ago
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John is making baked goods for a party. He can either make muffins or bread, and he can use blueberries, bananas, apples, or cho
Margarita [4]

The total number of possible choices that John had for making baked goods for the party is 8.

<h3>What is Combination?</h3>

The combination helps us to know the number of ways an object can be arranged without a particular manner. A combination is denoted by 'C'.

^nC_r = \dfrac{n!}{r!(n-r)!}

where,

n is the number of choices available,

r is the choices to be made.

We know that the number of choices with John for his baked goods is only two which are muffins or bread, therefore, the choices of the baked good can be written as ^2C_1.

Also, the number of choices with John for flavors is four which are blueberries, bananas, apples, or chocolate chips, therefore, the choices of the flavor can be written as ^4C_1.

Now, the total possible choices that John had

= The choices of the baked good x The choices of the flavor

=\ ^2C_1 \times ^4C_1\\\\=\ 8

Hence, the total number of possible choices that John had for making baked goods for the party is 8.

Learn more about Combination:

brainly.com/question/11732255

8 0
2 years ago
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