Answer:
Speed of Jet in Still Air = 265 miles per hour
Speed of Wind = 22 miles per hour
Step-by-step explanation:
Let x be speed of jet
and c be speed of wind
We know D = RT, where
D is distance
R is rate
T is time
For first leg:
1435 miles in 5 hours, the rate is:
Rate = 287 mph
For second leg:
1215 miles in 5 hours, the rate is:
Rate = 243 mph
So 287 is with wind and 243 against wind, thus we can write:
x + c = 287
x - c = 243
Adding gives us:
2x = 530
x = 265 miles per hour [still rate]
Speed of wind:
x + c = 287
265 + c = 287
c = 22 miles per hour [speed of wind]
I think it is 2/3X - 44
Hope this helps
Answer:
Given - a = 4
b = 9
c = 1
To find - Value of equation
Solution -
3b ÷ c^1 - a
Putting the value of a,b and c in the equation
3(9) ÷ (1)^1 - 4
27 ÷ 1 - 4
27 ÷ (-3)
27 × (1 /(-3)
27/(-3)
(-9)
Answer:
For a polynomial of the form ax2+bx+c a x 2 + b x + c , rewrite the middle term as a sum of two terms whose product is a⋅c=4⋅−25=−100 a ⋅ c = 4 ⋅ - 25 ...
Step-by-step explanation:
Answer:
here u go
Step-by-step explanation:
88%
