All categories

3 years ago

How to order -14.4, -14, -14 1/5 from least to greatest

1 answer:

8 0

Think of thermometer the negative degrees are the coldest so are the lowest on the vertical column

first convert -14 1/5 to decimals = -14.2

so the order is

-14.4 , -14 1/5 , -14.

You might be interested in

I will give brainliest. <br> What is the hypotenuse and how do I get it?

Ivan

Step-by-step explanation:

by Pythagoras theorem:

perpendicular² + base²= hypotenuse²

(1/√2)²+ (1/√3)² = H²

1/2+1/3= H²

5/6 = H²

√(5/6 )= H

√5/√6 = H

plz mark my answer as brainlist plzzzz.

hope this will be helpful to you

4 0

3 years ago

Please answer 7/10k=21 find x ill give you brainliest

algol [13]

Answer:

k=2.1

Step-by-step explanation:

7/10k=21

x7 x7 Multiply seven from each side of the equation.

10k=21

/10 /10 Divide ten from each side of the equation. 21/10=2.1

k=2.1

3 0

3 years ago

Expand this question: 6(x - 4y)

user100 [1]

6x-24y is the answer

8 0

2 years ago

8x + 11 = 2(4x - 7) + 25<br> Step by step please!

Dimas [21]

Step-by-step explanation:

8x + 11=2(4x-7) + 25

8x + 11 = 8x - 14 + 25

8x + 11=8x- 14 + 14 +25 + 11

8x-8x + 11 -11 = 14 + 25 + 11

8x-8x =14 + 25 + 11

X = 50

3 0

3 years ago

Consider a uniform distribution from aequals4 to bequals29. (a) Find the probability that x lies between 7 and 27. (b) Find th

weeeeeb [17]

Answer:

a) 80% probability that x lies between 7 and 27.

b) 28% probability that x lies between 6 and 13.

c) 44% probability that x lies between 9 and 20.

d) 28% probability that x lies between 11 and 18.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value x between c and d, in which d is larger than c, is given by the following formula.

$P(c \leq x \leq d) = \frac{d - c}{b - a}$

Uniform distribution from a = 4 to b = 29

(a) Find the probability that x lies between 7 and 27.

So $c = 7, d = 27$

$P(7 \leq x \leq 27) = \frac{27 - 7}{29 - 4} = 0.8$

80% probability that x lies between 7 and 27.

(b) Find the probability that x lies between 6 and 13. 

So $c = 6, d = 13$

$P(6 \leq x \leq 13) = \frac{13 - 6}{29 - 4} = 0.28$

28% probability that x lies between 6 and 13.

(c) Find the probability that x lies between 9 and 20.

So $c = 9, d = 20$

$P(9 \leq x \leq 20) = \frac{20 - 9}{29 - 4} = 0.44$

44% probability that x lies between 9 and 20.

(d) Find the probability that x lies between 11 and 18.

So $c = 11, d = 18$

$P(11 \leq x \leq 18) = \frac{18 - 11}{29 - 4} = 0.28$

28% probability that x lies between 11 and 18.

3 0

3 years ago