Question 4
1 answer:
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Answer:
e. 5.0329 g/mL
Step-by-step explanation:
Density is defined as mass divided by volume of an object. The volume displaced is:
#Density is then calculated as:
#Correct significant figures should correspond to the highest given in the question.
Hence the density of the metal is 5.0329g/mL
Answer:
x<56
Step-by-step explanation:
Since the dot over 56 isn't filled in, the inequality doesn't include 56 (so we'll use < or > not or
)
Now, let's look at the direction of the shading: is it going to the left of 56 or to the right?
This shading is to the left of 56, which indicates that it's all of the numbers less than 56.
As said above, the inequality doesn't include 56
therefore, it will be x<56 (x is less than 56, and 56 is not included)
hope this helps!
Answer:
a) <u>Alternative hypothesis:</u> the use of the coupons is isgnificantly higher than 10%.
<u>Null hypothesis:</u> the use of the coupons is not significantly higher than 10%.
The null and alternative hypothesis can be written as:
b) Point estimate p=0.13
c) At a significance level of 0.05, there is not enough evidence to support the claim that the proportion of coupons use is significantly higher than 10%.
Eagle should not go national with the promotion as there is no evidence it has been succesful.
Step-by-step explanation:
<em>The question is incomplete.</em>
<em>The sample data shows that x=13 out of n=100 use the coupons.</em>
This is a hypothesis test for a proportion.
The claim is that the proportion of coupons use is significantly higher than 10%.
Then, the null and alternative hypothesis are:
The significance level is 0.05.
The sample has a size n=100.
The point estimate for the population proportion is the sample proportion and has a value of p=0.13.
The standard error of the proportion is:
Then, we can calculate the z-statistic as:
This test is a right-tailed test, so the P-value for this test is calculated as:
As the P-value (0.202) is greater than the significance level (0.05), the effect is not significant.
The null hypothesis failed to be rejected.
At a significance level of 0.05, there is not enough evidence to support the claim that the proportion of coupons use is significantly higher than 10%.