Answer:
The greatest number of the books that could have been borrowed during the week is 36
Step-by-step explanation:
Let's create an equation which represent this problem, where will rest the book borrow and add the book returned to the 40 initial amount of book on Monday, to get the 22 book in the shelf on Saturday morning
40 (book on the shelf on Monday) - x (book borrowed) + 0.5 * x (50 % of the book was returned before Saturday) = 22 (books in the shelf on Saturday morning)
40 - x + 0.5 * x = 22
40 - 0.5*x = 22
18 = 0.5 * x
18/0.5 = x
36 = x
The amount of borrowed books is 36
Answer:
- as written, c ≈ 0.000979 or c = 4
- alternate interpretation: c = 0
Step-by-step explanation:
<em>As written</em>, you have an equation that cannot be solved algebraically.
(32^2)c = 8^c
1024c = 8^c
1024c -8^c = 0 . . . . . . rewrite as an expression compared to zero
A graphical solution shows two values for c: {0.000978551672551, 4}. We presume you're interested in c = 4.
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If you mean ...
32^(2c) = 8^c
(2^5)^(2c) = (2^3)^c . . . . rewriting as powers of 2
2^(10c) = 2^(3c) . . . . . . . simplify
10c = 3c . . . . . . . . . . . . . .log base 2
7c = 0 . . . . . . . . . . . . . . . subtract 3c
c = 0 . . . . . . . . . . . . . . . . divide by 7