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Art [367]
3 years ago
15

Prove

le="\lim_{x \to 0} \frac{sin x}{x} = 1" alt="\lim_{x \to 0} \frac{sin x}{x} = 1" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
SpyIntel [72]3 years ago
3 0

Answer:

See below.

Step-by-step explanation:

sin x / x.

You can prove this by L'Hopitals Rule.

If x = 0 then the function = 0/0 so the above rule is applicable here.

Differentiating top and bottom we get cos x / 1  = cos x.

Limit x --> 0 of cos x = 1 so it is proved.

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the bowling alley charges a flat rate of $50 for a birthday party plus $4.25 per person. If Emanuel only has $125 to spend. How
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divide by 4.25

p>17.64

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3 0
3 years ago
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2 years ago
Read 2 more answers
Suppose f(x)=x^2.What is the graph of g(x)=f(5x)?
ZanzabumX [31]

Answer:

D

Step-by-step explanation:

g(x)=f(5x)

this means plugging in 5x for x in f(x):

g(x)=f(5x)=(5x)^2

which can be further simplified:

5^2x^2=25x^2

Since the coefficient of x being larger means a vertical stretch, the answer is D

example:

g(2)=f(5*2)=f(10)=f(10^2)=100

so for g(x), it has the coordinates (2,100), which is most definitely not C

5 0
2 years ago
Point A is on a number line halfway between −17−17 and 55. Point B is halfway between point A and 0. What integer does the point
julia-pushkina [17]
Find A first by using formula: (a+b)/2= midpoint
so: A = [(-17)+(55)]/2
         = 36

Now find B using midpoint formula:
B: (a+b)/2 
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=18
6 0
3 years ago
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