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seropon [69]
3 years ago
14

5. Which equation defines the electric power P that a circuit delivers to a resistor?

Physics
1 answer:
MAVERICK [17]3 years ago
3 0

Answer: P = V^2 /R

Explanation:

P = IV

I = V/R

P = V^2 /R

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A young woman named kathy kool buys a sports car that can accelerate at the rate of 5.37 m/s 2 . she decides to test the car by
ohaa [14]

As the stan moves 0.94 s before with an acceleration 4.12 m/s^2

so the distance moved by it

d = \frac{1}{2}at^2[tex]d = \frac{1}{2}*4.12*0.94^2

d = 1.82 m

speed gained by the car is given as

v = v_i + at

v = 4.12* 0.94 = 3.873 m/s

now the relative speed of them is given as

v_r = 3.873 - 0 = 3.873 m/s

relative acceleration is given as

a_r = 4.12 - 5.37 = -1.25

now the distance between them is to be covered

d = v_r * t + \frac{1}{2}a_r * t^2

1.82 = -3.873* t + \frac{1}{2}*1.25 * t^2

by solving above equation we have

t = 6.64 s

so it will overtake after 6.64 s

5 0
3 years ago
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After reading the scenario, write which of the 3 ways is demonstrated and explain
Natasha2012 [34]

Answer:

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Explanation:

5 0
3 years ago
Kinetic energy of 110 j and velocity of 70 m/s what is the mass
VARVARA [1.3K]

Answer:

0.04kg

Explanation:

Explanation in pics:

The formula for kinetic energy is KE = 1/2mv². So now the question asks for the mass, not KE. So we need to rearrange the formula so that we are calculating the mass. So, the formula for mass is m=KE/(1/2v²). Now we just substitute the values into the formula. Then just follow what it shows in the pic

7 0
3 years ago
If a ball is thrown upward with an initial velocity of 30.0 m/s how much time does it take to reach its maximum height
Masteriza [31]
Gravity makes an upward-moving object move 9.8 m/s slower every second.

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3 0
3 years ago
A 0.100-kg stone rests on a frictionless, horizontal surface. A bullet of mass 6.00 g, travel- ing horizontally at 350 m>s, s
mariarad [96]

Answer:

Magnitude is 25.8 m/s and direction is 35.5^{o}

Explanation:

From the law of conservation of linear momentum

m_{b}v_{ib}+ m_{s}v_{is}= m_{b}v_{fb}+ m_{b}v_{fs} where m_{b} and m_{s} are masses of bullet and stones respectively, v_{ib} and v_{is} are the initial velocities of bullet and stone respectively, v_{fb} and v_{fs} are the final velocities of bullet and stone respectively

Substituting 6g=0.006 Kg for mass of bullet, 0.1Kg for mass of stone, 350 m/s for initial velocity of bullet and 250 m/s as final velocity for stone but initial velocity of stone is zero

0.006 Kg *350 m/s (\hat i)+0.1 Kg*0=0.006 Kg* 250 m/s (\hat j)+0.1*v_{fs}

2.1 Kg.m/s(\hat i)=1.5 Kg.m/s(\hat j)+ 0.1*v_{fs}

0.1*v_{fs}=2.1 Kg.m/s(\hat i)- 1.5 Kg.m/s(\hat j)

v_{fs}=21 Kg.m/s(\hat i)- 15 Kg.m/s(\hat j)

|v_{fs}|=\sqrt {(v_{x}^{2}+v_{y}^{2})}

Substituting 21 for v_{x} and 15 for v_{y}

|v_{fs}|=\sqrt {(21^{2}+15^{2})}=25.8 m/s

To find direction

tan\theta=\frac {v_{y}}{v_{x}}

\theta=tan^{-1}(\frac {15}{21})=35.5^{o}

Therefore, magnitude is 25.8 m/s and direction is 35.5^{o}

8 0
4 years ago
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