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pickupchik [31]
3 years ago
12

When performing an.experiment similar to Millikan's oil drop, a student measured the following load magnitudes: 3.26x10 ^-19 C 5

.09x10 ^-19 C 1.53x10 ^-19 C 6.39x10 ^-19 C 4.66x10 ^-19 C I used these measurements to find the charge on the electron
Physics
1 answer:
torisob [31]3 years ago
8 0

Answer:

Explanation:

We put the charges in the ascending order as follows

1.53 P

3.26 P

4.66 P

5.09 P

6.39 P

where P is equal to 10⁻¹⁹

we round off given charges as follows

1.53 P → 1.6 P

3.26 P → 3.2 P

4.66 P → 4.8 P

5.09 P → 4.8 P

6.39 P → 6.4 P

We see that 2 nd to 4 th charges are integral multiples of first charge . That means these charges are supposed to be made of combination of first charge . So first charge appears to be minimum possible charge .

Hence this charge may exist on single electron.

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It depends on how many hours!
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Write down formula of power​
r-ruslan [8.4K]
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A 4.5-kg, three legged stool supports a 89-kg person. If each leg of the stool has a cross-sectional diameter of 2.8 cm and the
kkurt [141]

Answer:

4.96 × 10⁵ Pa

Explanation:

F = mg

F = (m_{person}+m_{stool})g\\\\F =  (4.5 + 89)*9.8\\\\F = 916.3 N

This force is evenly distributed on the three leg

radius, r = d/2

= 2.8 / 2

= 1.4 cm = 0.014 m

total cross sectional area of the three legs, A = 3*pi*r^2

= 3\times\pi \times0.014^2\\\\= 1.847\times10^-^3m^2

Pressure due to weight,

P = Weight/A

P = / 1.847 × 10⁻³\\P = \frac{ 916.3N}{1.847\times10^-^3} \\\\P= 496032.9Pa

P = 4.96 × 10⁵ Pa

8 0
3 years ago
What is the resolution of an analog-to-digital converter with a word length of 12 bits and an analogue signal input range of 100
Elena L [17]

Answer:

The resolution of an analog-to-digital converter is 24.41 mV

Explanation:

Resolution of an analog-to-digital  = (analogue signal input range)/2ⁿ

where;

n is the number or length of bit, and in this question it is given as 12

Also, the analogue signal input range is 100V

Resolution of an analog-to-digital  = 100V/2¹²

2¹² = 4096

Resolution of an analog-to-digital  = 100V/4096

Resolution of an analog-to-digital  = 0.02441 V = 24.41 mV

Therefore, the resolution of an analog-to-digital converter is 24.41 mV

5 0
3 years ago
What is the total kinetic energy of a 0.15 kg hockey puck sliding at 0.5 m/s and rotating about its center at 8.4 rad/s
AlexFokin [52]

Answer:

K=0.023J

Explanation:

From the question we are told that:

Mass m=0.15

Velocity v=0.5m/s

Angular Velocity \omega=8.4rad/s

Generally the equation for Kinetic Energy is mathematically given by

K=\frac{1}{2}M(v^2+\frac{1}{2}R^2\omega^2)

K=\frac{1}{2}0.15(0.5^2+\frac{1}{2}(0.038)^2.(8.4rad/s^2))

K=0.023J

8 0
2 years ago
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