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pickupchik [31]
3 years ago
12

When performing an.experiment similar to Millikan's oil drop, a student measured the following load magnitudes: 3.26x10 ^-19 C 5

.09x10 ^-19 C 1.53x10 ^-19 C 6.39x10 ^-19 C 4.66x10 ^-19 C I used these measurements to find the charge on the electron
Physics
1 answer:
torisob [31]3 years ago
8 0

Answer:

Explanation:

We put the charges in the ascending order as follows

1.53 P

3.26 P

4.66 P

5.09 P

6.39 P

where P is equal to 10⁻¹⁹

we round off given charges as follows

1.53 P → 1.6 P

3.26 P → 3.2 P

4.66 P → 4.8 P

5.09 P → 4.8 P

6.39 P → 6.4 P

We see that 2 nd to 4 th charges are integral multiples of first charge . That means these charges are supposed to be made of combination of first charge . So first charge appears to be minimum possible charge .

Hence this charge may exist on single electron.

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C. Airplane,bird,butterfly
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3 years ago
5. George walks to a friend's house. He walks 750 meters North, then realizes he walked too far.
dedylja [7]

Answer:

Average speed: approximately 76.9\; {\rm m\cdot s^{-1}}.

Average velocity: approximately 38.5\; {\rm m \cdot s^{-1}} (to the north.)

Explanation:

Consider an object that travelled along a certain path. Distance travelled would be equal to the length of the entire path.

In contrast, the magnitude of displacement is equal to distance between where the object started and where it stopped.

In this question, the path George took required him to travel 750\; {\rm m} + 250\; {\rm m} = 1000\; {\rm m} in total. Hence, the distance George travelled would be 1000\; {\rm m}. However, since George stopped at a point (750\; {\rm m} - 250\; {\rm m}) = 500\; {\rm m} to the north of where he started, his displacement would be only 500\; {\rm m} to the north.

Divide total distance by total time to find the average speed.

Divide total displacement by total time to find average velocity.

The total time of travel in this question is 13\; {\rm s}.. Therefore:

\begin{aligned}\text{average speed} &= \frac{\text{total distance}}{\text{total time}} \\ &= \frac{1000\; {\rm m}}{13\; {\rm s}} \\ &\approx 76.9\; {\rm m\cdot s^{-1}}\end{aligned}.

\begin{aligned}\text{average velocity} &= \frac{\text{total displacement}}{\text{total time}} \\ &= \frac{500\; {\rm m}}{13\; {\rm s}} && \genfrac{}{}{0px}{}{(\text{to the north})}{}\\ &\approx 38.5\; {\rm m\cdot s^{-1}} && (\text{to the north})\end{aligned}.

3 0
2 years ago
Question 15
lozanna [386]

Answer:

Time use of cellphone times 3 hours before sleep.

Explanation:

It is scientifically proven that cell-phone use before bed can disturb your sleep. The blue light can cause your brain to release chemicals that associate with staying awake or even waking up. So measure the hours or minutes you use your phone 3 hours before you go to sleep.

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11.) If figure skater spins with a circular acceleration of 275 m/s^2 in a circle 5 poin with a radius of 0.55 meters, calculate
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Answer:

we don't care what ure saying thats absurd

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A spring, having an unstretched length of 2ft, has one end attached to the 10lb ball. determine the angle ? of the spring if the
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The angle theta of the spring is 31 degrees. To solve for this, show the equation which is equal to the 10lb ball. With this, the unknown will be the angle. Then transpose/transfer the terms in order to isolate the variable for the angle. First solve for s, then solve for angle theta. You will come up with s = .5849 ft and angle theta = 31.2629 or 31 degrees. Hope this helps.
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