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3 years ago

Difference between calorimeter and thermometer ?

2 answers:

6 0

A calorimeter is can be used to measure the amount of heat released or involved in a chemical reaction. Whereas thermometer can only measures temperature or hotness of a substance. It cannot be used to measure the thermal rate or amount of heat energy of a reaction.

Helen [10]3 years ago

4 0

Answer:

Explanation:

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A laser beam of unknown wavelength passes through adiffraction grating having 5510 lines/cm after striking itperpendicularly. Ta

Ivahew [28]

Answer:

Explanation:

distance between two slit d = $\frac{1 \times 10^{-2}}{5510}$

d = 18.15 x 10⁻⁷ m

Let wave length of light λ

formula for position of first pair of bright spot

Tanθ = λ / d , λ is wave length of light and d is distance between two slit .

Tan 15.4 = $\frac{\lambda}{18.15\times10^{-7}}$

λ = Tan 15.4 x 18.15 x 10⁻⁷

=5 x 10⁻⁷ m

If θ be the position of next bright spot

Tanθ = 2 λ / d

= $\frac{2 \times\ 5\times\ 10^ {-7}}{18.15\times10^{-7}}$

= $\frac{2\times5}{18.5}$

θ = 28.4 degree .

7 0

3 years ago

A stream of warm water is produced in a steady-flow mixing process by combining 1.0 kg/s of cool water at 25 °C with 0.8 kg/s of

Tamiku [17]

Explanation:

The given data is as follows.

$m_{1}$ = 0.8 kg/s = 800 g, $C_{1} = 4.18 J/g^{o}C$

$m_{2}$ = 1 kg = 1000 g, $T_{1}$ = (75 - T),

$T_{2}$ = T - 25

Now, according to the law of conservation of energy,

$m_{1}C_{1}T_{1} = m_{2}C_{2}T_{2} + mL$

$800 \times 4.18 \times (75 - T) = 1000 \times 4.18 \times (T - 25)$ + 30000

250.8 - 3.34T = 4.18T - 104.5 + 30

T = $\frac{325.3}{7.52}$

= $43.23^{o}C$

Thus, we can conclude that temperature of the warm water stream is $43.23^{o}C$ .

4 0

2 years ago

When are ionic bonds formed

allochka39001 [22]

Answer:

ionic bonds formed from the electrostatic attraction between oppositely charged ions in a chemical compound.

Explanation:

5 0

2 years ago

When heat is removed from a substance , describe how the molecules are affected

kkurt [141]

I believe they would electron rate would slow down and the molecules would shrink.

I am almost positive that this is correct. I hope it helps!

6 0

3 years ago

Read 2 more answers

What is the reflectivity of a glass surface (n =1.5) in air (n = 1) at an 45° for (a) S-polarized light and (b) P-polarized ligh

Goshia [24]

Answer:

a) $R_s = 0.092$

b) $R_p = 0.085$

Explanation:

given,

n =1.5 for glass surface

n = 1 for air

incidence angle = 45°

using Fresnel equation of reflectivity of S and P polarized light

$R_s=\left | \dfrac{n_1cos\theta_i-n_2cos\theta_t}{n_1cos\theta_i+n_2cos\theta_t} \right |^2\\R_p=\left | \dfrac{n_1cos\theta_t-n_2cos\theta_i}{n_1cos\theta_t+n_2cos\theta_i} \right |^2$

using snell's law to calculate θ t

$sin \theta_t = \dfrac{n_1sin\theta_i}{n_2}=\dfrac{sin45^0}{1.5}=\dfrac{\sqrt{2}}{3}$

$cos \theta_t =\sqrt{1-sin^2\theta_t} = \dfrac{sqrt{7}}{3}$

a) $R_s=\left | \dfrac{\dfrac{1}{\sqrt{2}}-\dfrac{1.5\sqrt{7}}{3}}{\dfrac{1}{\sqrt{2}}+\dfrac{1.5\sqrt{7}}{3}} \right |^2$

$R_s = 0.092$

b) $R_p=\left | \dfrac{\dfrac{\sqrt{7}}{3}-\dfrac{1.5}{\sqrt{2}}}{\dfrac{\sqrt{7}}{3}+\dfrac{1.5}{\sqrt{2}}} \right |^2$

$R_p = 0.085$

3 0

3 years ago