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Yuri [45]
4 years ago
8

What is the solution to –4(8 – 3x) ≥ 6x – 8?

Mathematics
2 answers:
Nat2105 [25]4 years ago
8 0
Hi there!

- 4(8 - 3x) \geqslant 6x - 8
First work out the parenthesis. Remember that a negative times a positive ends up with a negative. A negative times a negative ends up with a positive.

- 32 + 12x \geqslant 6x - 8
Subtract 6x from both sides.

- 32 + 6x \geqslant  - 8
Add 32 to both sides.

6x \geqslant 24
Divide both sides by 6.

x \geqslant 4
Now we've found our solution.
~ Hope this helps you!




gtnhenbr [62]4 years ago
4 0
The answer: <span><span>x≥4
hope i helped
</span></span>
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