Question

What is the solution to –4(8 – 3x) ≥ 6x – 8?

Answer 1

Hi there!

$- 4(8 - 3x) \geqslant 6x - 8$
First work out the parenthesis. Remember that a negative times a positive ends up with a negative. A negative times a negative ends up with a positive.

$- 32 + 12x \geqslant 6x - 8$
Subtract 6x from both sides.

$- 32 + 6x \geqslant - 8$
Add 32 to both sides.

$6x \geqslant 24$
Divide both sides by 6.

$x \geqslant 4$
Now we've found our solution.
~ Hope this helps you!

Answer 2

The answer: x≥4
hope i helped