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trapecia [35]
3 years ago
10

A turtle is 20 5/6 inches below the surface of a pond. It dives to a depth of 32 1/4 inches. What is the change in the turtle’s

position? Write your answer as a mixed number.
Mathematics
1 answer:
Naddik [55]3 years ago
5 0
Change=new-original
change=32 and 1/4-20 and 5/6
32 and 1/4-20 and 5/6=
32+1/4-(20+5/6)=
32+1/4-20-5/6=
32-20+1/4-5/6=
1/4 and 5/6
LCD=12
1/4 times 3/3=3/12
5/6 times 2/2=10/12

32-10+3/12-10/12=
12-7/12=
11+12/12-7/12=
11+5/12
the turtle went down so the change is negative

the change is -11 and 5/12 inches
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Answer:

a. See Attachment 1

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Step-by-step explanation:

Calculating PT

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We have to consider angle 50, distance OH and distance OT

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--------------------------------------------------------

Calculating the distance between H and the top of the tower

This is represented by HT

HT can be calculated using Pythagoras theorem

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HT^2 = 20^2 + 23.836^2

HT^2 = 400 + 568.154896

HT^2 = 968.154896

Take Square Root of both sides

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HT = 31.1\ m <em>(Approximated)</em>

--------------------------------------------------------

Calculating the position of H

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See Attachment 2

We have to consider angle 50, distance OH and distance OT

The relationship between these parameters is;

tan50 = \frac{OH}{OT}

Multiply both sides by OT

OT * tan50 = \frac{OH}{OT} * OT

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Substitute OT = 23.836

23.836 * 1.1918 = OH

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