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Musya8 [376]
3 years ago
9

Can someone help me with this question

Mathematics
2 answers:
Alchen [17]3 years ago
7 0

Answer:

c is the right one

Step-by-step explanation:

Fofino [41]3 years ago
6 0
Answer B
I could be wrong
Explanation
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Type the correct answer in the box. Round your answer to the hundredth.
sesenic [268]

Answer:

Approximately 22.97 years

Step-by-step explanation:

Use the equation for continuously compounded interest, which uses the exponential base "e":

A=P e^{k*t}

Where P is the principal (initial amount of the deposit - unknown in our case)

A is the accrued value (value accumulated after interest is compounded), in our case it is not a given value but we know that it triples the original deposit (principal) so we write it as: 3 P (three times the principal)

k is the interest rate : 5% which translates into 0.05

and t is the time in the savings account to triple its value (what we need to find)

The formula becomes:

3P = P e^{0.05 * t}

To solve for "t" we divide both sides of the equation by P (notice it cancels P everywhere), and then to solve for the exponent "t" we use the natural logarithm function:

\frac{3P}{P} = \frac{P}{P}  e^{0.05 * t}

3 = e^{0.05 * t}

ln(3) = 0.05 * t

t = \frac{ln(3)}{0.05} = 21.972245... years

6 0
3 years ago
Arianna has a coin collection. She keeps 4 of the coins in her box, which is 10% of the
natima [27]

Answer: 40 coins. Doesn't your profile say college?

5 0
3 years ago
Please help!!!<br> Which expression is equivalent to (3m^-1n^2)^4/(2m^-2n)^3
Elza [17]
\text{Use:}\\\\(a\cdot b)^n=a^nb^n\\\\(a^n)^m=a^{n\cdot m}\\\\\dfrac{a^n}{a^m}=a^{n-m}

\dfrac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}=\dfrac{3^4(m^{-1})^4(n^2)^4}{2^3(m^{-2})^3n^3}=\dfrac{81m^{-4}n^8}{8m^{-6}n^3}\\\\=10.125m^{-4-(-6)}n^{8-3}=10.125m^2n^5
7 0
3 years ago
Read 2 more answers
A2 + b2 = n2 because of the
Nataly_w [17]
Phytagorean Theorem i think
3 0
3 years ago
Read 2 more answers
HELP RIGHT NOW AND ILL GIVE BRAINLY IF CORRECT
Stella [2.4K]

Answer:

-9

Step-by-step explanation:

3^{-36}= 27^{-12}

7 0
3 years ago
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