All categories

2 years ago

What is the y-intercept of the line y=7?

Mathematics

1 answer:

Maru [420]2 years ago

3 0

Answer:

Step-by-step explanation:

The value of the y-intercept is (0,7)

So the y intercept is 0,7

You might be interested in

Given the functions below, find (f - g) (2).<br> f(x)<br> x2 + 3<br> g(x) = 4x – 3<br> =

kakasveta [241]

Answer:

(f - g)(2) = 2

Step-by-step explanation:

Given the functions below, find (f - g) (2).

f(x) = x² + 3

g(x) = 4x – 3

(f - g)(x) = (x²+3)-(4x-3)

(f - g)(x) = x²+3-4x+3

(f - g)(x) = x²-4x+6

(f - g)(2) = (2)²-4(2)+6

(f - g)(2) = 4-8+6

(f - g)(2) = 2

5 0

2 years ago

If g(x) is the inverse of f(x)=4x+12 and f(x)=, what is g(x)

Nitella [24]

Hello,
f(x)=y=4x+12

x=4y+12
==>4y=x-12
==>y=x/12- 3

g(x)=x/12 -3

6 0

3 years ago

Read 2 more answers

A trucking firm has a large inventory of spare parts that have been in storage for a long time. It knowsthat some proportion of

Debora [2.8K]

Answer:

$0.1546\leq \widehat{p}\leq 0.3513$

Step-by-step explanation:

The firm tests 75 parts, and finds that 0.25 of them are notusable

n = 75

x = 0.25 \times 75 = 18.75≈19

$\widehat{p}=\frac{x}{n}$

$\widehat{p}=\frac{19}{75}$

$\widehat{p}=0.253$

Confidence level = 95%

So, Z_\alpha at 95% = 1.96

Formula of confidence interval of one sample proportion:

$=\widehat{p}-Z_\alpha \sqrt{\frac{\widehat{p}(1-\widehat{p}}{n}}\leq \widehat{p}\leq \widehat{p}+Z_\alpha \sqrt{\frac{\widehat{p}(1-\widehat{p}}{n}}$

$=0.253-(1.96)\sqrt{\frac{0.253(1-0.253)}{75}}\leq \widehat{p}\leq0.253+(1.96)\sqrt{\frac{0.253(1-0.253}{75}}$

Confidence interval $=0.1546\leq \widehat{p}\leq 0.3513$

7 0

3 years ago

What the extreme point on the parabola

ki77a [65]

Answer:

Directrix

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

There are s swimmers in the swimming club. The club bought 15 swimming caps to split among its members. Write an expression that

vivado [14]

Answer:

15/s

Step-by-step explanation:

15 caps ÷ s = 15/s caps per swimmer

6 0

2 years ago