Bria ordered 145 centimeters of fabric. Jayleen ordered 1.5 meters of fabric. Who ordered more fabric?
Answer:
The p-value for the test is 0.0459.
Explanation:
The question involves a chi-squared test whose p-value is to be determined.
H₀: σ² ≤ 0.027 (null hypothesis)
H₁: σ² > 0.027 (alternative hypothesis)
Standard deviation = s = 0.2
Hence, s² = (0.2)² = 0.04
Sample size = n = 30
Degree of freedom = n - 1 = 30 - 1 = 29
Significance level = 0.05
Test statistic: X² = (n - 1)s² / σ²
= (30 - 1) x 0.04 / 0.027
= 42.9629
The p-value can now be determined using the Excel function:
CHISQ.DIST.RT(42.9629,29) = 0.0459
Hence, the p-value for the test is 0.0459.
Answer:
Martin family: 20 hours
Lewis family: 35 hours
Step-by-step explanation:
Let's say that the Lewis family sprinklers were out for L hours and the Martin family's sprinklers were out for M hours. We know that for each hour that the Lewis family sprinkler was on, 30L of water was put out. We can thus write the Lewis family sprinkler water output as 30L per each hour of L = 30 * L. Similarly, the Martin family sprinkler water output = 15 * M .
We know that the total hours for the sprinklers is 55, so L + M = 55. The total water output for the sprinklers is the sum of the sprinkler outputs, so 30 * L + 15 * M = 1350
L + M = 55
30 * L + 15 * M = 1350
One way to solve this would be to solve for L in the first equation and substitute that into the second
subtract M from both sides in the second equation
55 - M = L
30 * (55-M) + 15 * M = 1350
30 * 55 - 30 * M + 15 * M = 1350
1650 - 15M = 1350
subtract 1650 from both sides to isolate the M and its coefficient
-15M = -300
divide both sides by -15 to isolate M
M = 20
L = 55-20 = 35
Gg easey
perimiter is jsut the sum of the measures of the sides
P=2.3x+14+2x-0.2x+15
group like terms
P=2.3x+2x-0.2x+14+15
add
P=4.1x+29
answer is first one
10% because walking is only 10 percent of the hrs
