-5h-3(10+h) = -6
-5h-30-3h = -6
Add/subtract like terms
-8h -30 = -6
Add 30 to both sides
-8h = 24
Divide by -8 to isolate h
h = -3
(tanθ + cotθ)² = sec²θ + csc²θ
<u>Expand left side</u>: tan²θ + 2tanθcotθ + cot²θ
<u>Evaluate middle term</u>: 2tanθcotθ =
= 2
⇒ tan²θ + 2+ cot²θ
= tan²θ + 1 + 1 + cot²θ
<u>Apply trig identity:</u> tan²θ + 1 = sec²θ
⇒ sec²θ + 1 + cot²θ
<u>Apply trig identity:</u> 1 + cot²θ = csc²θ
⇒ sec²θ + csc²θ
Left side equals Right side so equation is verified
7 2
12 5
Do the reciprocal!
7 5
12 2
And just multiply and you get 35/24
There are 10 deciliters in 1 liter (deci means 10).
Divide 5.25 by 10 to find how many liters are needed.
5.25/10 = 0.525
0.525 liters of milk are needed for the cake.
I think it’s -1 please mark brainly