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Agata [3.3K]
3 years ago
10

you plant 15 tulip bulbs and 10 of them grow into flowers to bloom. If you plant 21 more re tulips bulbs, predict how many of th

em would bloom
Mathematics
1 answer:
harina [27]3 years ago
5 0

Answer:

14 more flower would bloom if 21 more tulip bulb is planted.

Step-by-step explanation:

Given ratio for tulip bulbs and flowers is 15:10.

Now, finding number of flower to bloom if 21 tulip bulb are planted.

Assume if 21 tulip bulbs are planted then number of flower would bloom be"x"

ratio given: \frac{Tulip\ bulbs}{ Flower} = \frac{15}{10} = \frac{21}{x}

Cross multiplying the ratio to get:

⇒x= \frac{21\times 10}{15} = \frac{210}{15}

∴x= 14\ flowers

Hence, 14 flowers would bloom if 21 tulip bulb are planted.

If total tulip bulb is 15+21= 36, then 10+14= 24\ flowers would bloom.

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gregori [183]

a= μ-3.16*σ , b= μ+3.16*σ if each fish caught is equally likely to be any one of these 4 distinct types.

<h3>What is meant by Chebyshev inequality?</h3>

Chebyshev's inequality is a probability theory that ensures that, over a vast range of probability distributions, no more than a particular proportion of values would be present within a selected limits or range as from mean. In other words, only a certain fish caught will be discovered within a given range of the distribution's mean.

The formula for which no more than a particular number of values can exceed is 1/K2; in other words, 1/K2 of a distribution's values can be more than or equal to K standard deviations away from the distribution's mean. Furthermore, it asserts that 1-(1/K2) of a distribution's values must be within, but not include, K standard deviations of the distribution's mean.

How to solve?

from Chebyshev's inequality for Y

P(| Y - μ|≤ k*σ ) ≥ 1-1/k²

where

Y =  the number of fish that need be caught to obtain at least one of each type

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k= parameter

thus for

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P{a≤Y≤b} ≥ 0.90 →  1-1/k² = 0.90 → k = 3.16

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using one-sided Chebyshev inequality (Cantelli's inequality)

P(Y- μ≥ λ) ≥ 1- σ²/(σ²+λ²)

P{Y≥b} ≥ 0.90  →  1- σ²/(σ²+λ²)=  1- 1/(1+(λ/σ)²)=0.90 → 3= λ/σ → λ= 3*σ

then for

P(Y≥ μ+3*σ ) ≥ 0.90

In order to learn more about Chebyshev inequality, visit:

brainly.com/question/24971067

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4 0
1 year ago
Micheal is 3 times as old as Brandon. 18 years ago, Micheal was 9 times as old as Brandon.
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Step-by-step explanation:

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6×9=54

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2 years ago
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x = 13  answer

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