What is the distance between the points (-6, 7) and (-1, 1) ? Round to the nearest whole number

Mathematics

1 answer:

pogonyaev2 years ago

8 0

Answer:

7.8 rounded to the nearest whole number would be 8.

Step-by-step explanation:

-6 would be x1

7 would be y1

-1 would be x2

1 would be y2

Take these numbers and plug them into the distance formula:

$\sqrt{(x2-x1)^{2} + (y2-y1)^2}$

$\sqrt{(-1 - -6)^2 + (1-7)^2} \\\sqrt{(5)^2 + (6)^2\\\} \\\sqrt{25 + 36} \\\sqrt{61} = 7.81$

You might be interested in

The polynomial equation x^3+x^2=-9x-9 has complex roots +/-3i What is the other root? Use a graphing calculator and a system of

Ierofanga [76]

For this case what you can do is factorize the polynomial equation, which would be left like follows
x ^ 3 + x ^ 2 + 9x + 9 = 0
(x + 1) (x ^ 2 + 9) = 0
Resolving, we have that the missing root is
x = -1
Answer
x=-1

7 0

3 years ago

2 (3p+5)= help me fats

Colt1911 [192]

Distribute

2 × 3p + 2 × 5

Simplify 2 × 3p to 6p

6p + 2 × 5

Simplify 2 × 5 to 10

6p + 10

7 0

3 years ago

Read 2 more answers

Find all values of c such that c/(c - 5) = 4/(c - 4). If you find more than one solution, then list the solutions you find separ

Deffense [45]

Answer:

$\large\boxed{\bold{NO\ REAL\ SOLUTIONS}}\\\boxed{x=4-2i,\ x=4+2i}$

Step-by-step explanation:

$Domain:\\c-4\neq0\ \wedge\ c-5\neq0\Rightarrow c\neq4\ \wedge\ c\neq5\\\\\dfrac{c}{c-5}=\dfrac{4}{c-4}\qquad\text{cross multiply}\\\\c(c-4)=4(c-5)\qquad\text{use the distributive property}\\\\c^2-4c=4c-20\qquad\text{subtract}\ 4c\ \text{from both sides}\\\\c^2-8c=-20\qquad\text{add 20 to both sides}\\\\c^2-8c+20=0\qquad\text{use the quadratic formula}$

$\text{for}\ ax^2+bx+c=0\\\\\text{if}\ b^2-4ac0,\ \text{then the equation has two solutions}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x^2-8x+20=0\\\\a=1,\ b=-8,\ c=20\\\\b^2-4ac=(-8)^2-4(1)(20)=64-80=-16$

$\text{In the set of complex numbers:}\\\\i=\sqrt{-1}\\\\\text{therefore}\ \sqrt{b^2-4ac}=\sqrt{-16}=\sqrt{(16)(-1)}=\sqrt{16}\cdot\sqrt{-1}=4i\\\\x=\dfrac{-(-8)\pm4i}{2(1)}=\dfrac{8\pm4i}{2}=\dfrac{8}{2}\pm\dfrac{4i}{2}=4\pm2i$