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Dvinal [7]
3 years ago
8

Lydia made $56,750 last year. She paid $1200 in student loan interest and made a $3000 contribution to her IRA. On her federal t

ax return, she will claim $4200 to be the amount of her _____. A.standard deduction B.AGI C.taxable income D.adjustments
Mathematics
2 answers:
USPshnik [31]3 years ago
6 0
The correct answer that would complete the given statement above would be option D. ADJUSTMENTS. Lydia made $56,750 last year. She paid $1200 in student loan interest and made a $3000 contribution to her IRA. On her federal tax return, she will claim $4200 to be the amount of her ADJUSTMENTS. Hope this answer helps.
Rus_ich [418]3 years ago
5 0

Answer:

adjustments

Step-by-step explanation:

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During the 7th examination of the Offspring cohort in the Framingham Heart Study, there were 1219 participants being treated for
AlexFokin [52]

Answer:

95% confidence interval for the proportion of the population which are on treatment is [0.3293 , 0.3607].

Step-by-step explanation:

We are given that during the 7th examination of the Offspring cohort in the Framing ham Heart Study, there were 1219 participants being treated for hypertension and 2,313 who were not on treatment.

The sample proportion is :  \hat p = x/n = 1219/3532 = 0.345

Firstly, the pivotal quantity for 95% confidence interval for the proportion of the population is given by;

      P.Q. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion = 0.345

           n = sample of participants = 3532

           p = population proportion

<em>Here for constructing 95% confidence interval we have used One-sample z proportion statistics.</em>

So, 95% confidence interval for the population​ proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level of

                                                         significance are -1.96 & 1.96}

P(-1.96 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

P( \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

<u>95% confidence interval for p</u>= [\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }]

    = [ 0.345-1.96 \times {\sqrt{\frac{0.345(1-0.345)}{3532} } } , 0.345+1.96 \times {\sqrt{\frac{0.345(1-0.345)}{3532} } } ]

    = [0.3293 , 0.3607]

Hence, 95% confidence interval for the proportion of the population which are on treatment is [0.3293 , 0.3607].

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3 years ago
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Dovator [93]
The second one is right
8 0
3 years ago
1. 3,742 x 6= help with step by step
xenn [34]

Answer: The answer is 22,452

Step-by-step explanation: Multiply 6×2 which will be 12

Put the 1 from the 12 on top of the 4 then do 4×6+1 it will equal 25

Then put the 2 on top of the 7 then do 7×6+2 it will equal 44

Then put the 4 on top of the 3 then do 3×6+4 it will equal 22

And that's how you get your answer.

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3 years ago
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