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2 years ago

The sum of a number and three more than the number.

Mathematics

1 answer:

Likurg_2 [28]2 years ago

7 0

Answer:

Step-by-step explanation:

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At Harry's discount hardware everything is sold for 20 percent less than the price marked. If Harry buys tool kits for $80,what

ICE Princess25 [194]

Answer:

$120.

Step-by-step explanation:

The amount he sells the tool kit for = 80 + 20% of 80

= 80 + 16

= $96.

Let m be the marked price, then

m - 0.20m = 96

0.8m = 96

m = $120.

5 0

3 years ago

Help me plzzzzzzzzzz??

julia-pushkina [17]

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

In a garden club, 90% i ladie. The number of ladie i 12 more than 3 time the number of gentlemen. How many ladie and how many ge

wariber [46]

In the garden club there are 18 ladies and 2 gentlemen.

Given, In a garden club, 90% is ladies.

The number of ladies is 12 more than 3 times the number of gentlemen.

Let the total members be, x

the number of ladies be, l and the number of gentlemen be, g

according to the question,

l = 90x/100

l = 9x/10

also, l = 12 + 3g

g = (l - 12)/3

as, l + g = x

9x/10 + (9x/10 - 12)/3 = x

9x/10 + 9x/30 - 4 = x

36x/30 - 4 = x

6x/30 = 4

x = 20

so, ladies be, l = 9x/10 = 18

and gentlemen be, g = 20 - 18 = 2

Hence, in the garden club there are 18 ladies and 2 gentlemen.

Learn more about Linear Equations here brainly.com/question/25869125

#SPJ4

4 0

1 year ago

Help ASAP also Pls put explanation along with answer (#7)

uysha [10]

I first think that you need to do 64 squared which is 8 then add the other 8 then you have 16 then do 16 square which equals 4 then I think you do 4 x 3 then add 25 then you get your answer..... hopefully

8 0

3 years ago

The temperature at any random location in a kiln used in the manufacture of bricks is normally distributed with a mean of 1000 a

NeX [460]

Answer:

b. 2.28%.

Step-by-step explanation:

Mean temperatue (μ) = 1000°F

Standard Deviation (σ) = 50 °F

For any temperature value, X, the z-score is given by:

$z=\frac{X-\mu}{\sigma}$

For X= 900°F

$z=\frac{900-1000}{50}\\z=-2.0$

A z-score of -2.0 corresponds to the 2.28-th percentile of a normal distribution. Therefore, the probability that X<900 is:

$P(X$

7 0

3 years ago