Answer:
1/(x^3 + 6x^2 + 12x + 8)
Step-by-step explanation:
The first thing we do is rationalize this expression. (2+x)^-3 is written as
1/(2+x)^3
Then from there we can foil out the denominator. It is easiest to foil (2+x)(2+x) first and then multiply that product by (2+x).
(2+x)(2+x) = 4 + 4x + x^2
(4+4x+x^2)(2+x) = 8+8x+2x^2+4x+4x^2+x^3.
Then we combine like terms and put them in order to get:
x^3 + 6x^2 + 12x + 8
And of course we can't forget that this was raised to the negative third power, so our answer is 1/(x^3 + 6x^2 + 12x + 8)
Answer:
11.5 in
Step-by-step explanation:
The equation you can use to relate L to D uses the information in the first part of the problem. First, if we just add 4 miles every day (ignoring the other piece), the length of the road would be 4 times the number of days, or L = 4D. But since we started with 57 miles built, we have to add that in order to get the total length, so the equation would be:
L = 4D + 57
You can use this question to find any value of L or D if you know one of them. According to the questoin, we know the crew worked 34 days (or D). So if you plug in 34 for D you'll get:
L = 4(34) + 57 ->
L = 136 + 57 ->
L = 193
The average rate of change of a function f(x) in an interval, a < x < b is given by

Given q(x) = (x + 3)^2
1.) The average rate of change of q(x) in the interval -6 ≤ x ≤ -4 is given by

2.) The average rate of change of q(x) in the interval -3 ≤ x ≤ 0 is given by

3.) The average rate of change of q(x) in the interval -6 ≤ x ≤ -3 is given by

4.) The average rate of change of q(x) in the interval -3 ≤ x ≤ -2 is given by

5.) The average rate of change of q(x) in the interval -4 ≤ x ≤ -3 is given by

6.) The average rate of change of q(x) in the interval -6 ≤ x ≤ 0 is given by