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2 years ago

Determine which postulate or theorem can be used to prove that REM= DME.

Mathematics

2 answers:

Snowcat [4.5K]2 years ago

5 0

Answer:

SSS

Step-by-step explanation:

REM and DME share a side. This side is of course congruent.

In addition, sides RM and ED are marked as congruent, as are RE and MD.

All three corresponding sides of each triangle are congruent, which proves the triangles' congruency.

No information is given about the angles in these triangles, so none of the other theorem answer choices are valid.

Please mark brainliest! :)

Valentin [98]2 years ago

5 0

Answer: SSS

Step-by-step explanation: APEX

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SpyIntel [72]

Answer:

Step-by-step explanation:

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2 years ago

As part of his math assignment, Santos has to estimate the height

ycow [4]

Answer:

105.46 feet

Step-by-step explanation:

We know all three angles (60, 90, and 30), as well as one side, which is adjacent to the 60 degrees. We want to find the side opposite to the 60 degree angle. To do this, we can use tangent, utilizing both opposite and adjacent.

Using tan, we can say that tan(60) = x/58, with x representing the height of the lighthouse (minus 5, because Santos is 5 feet tall and he is measuring the angle from the top of his head). Multiplying both sides by 58, we can get that 58 *tan(60) = x = 100.46. Add 5 to that to get 105.46 feet as your answer.

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2 years ago

I needddd heelpppp please

Nostrana [21]

Okay I am not 100% sure because that is an extremely confusing question. But here is what I got.

(A) 2c² = 2bc + ac/2 Given

(B) 4c² = 2bc + ac Multiplication and Distribution

(C) 4c = 4b + a Division and Distribution

(D) 4c - a + 4b Subtraction

(E) 4b = 4c - a Symmetric

6 0

3 years ago

You are creating an open top box with a piece of cardboard that is 16 x 30“. What size of square should be cut out of each corne

Arada [10]

Answer:

$\frac{10}{3} \ inches$ of square should be cut out of each corner to create a box with the largest volume.

Step-by-step explanation:

Given: Dimension of cardboard= 16 x 30“.

As per the dimension given, we know Lenght is 30 inches and width is 16 inches. Also the cardboard has 4 corners which should be cut out.

Lets assume the cut out size of each corner be "x".

∴ Size of cardboard after 4 corner will be cut out is:

Length (l)= $30-2x$

Width (w)= $16-2x$

Height (h)= $x$

Now, finding the volume of box after 4 corner been cut out.

Formula; Volume (v)= $l\times w\times h$

Volume(v)= $(30-2x)\times (16-2x)\times x$

Using distributive property of multiplication

⇒ Volume(v)= $4x^{3} -92x^{2} +480x$

Next using differentiative method to find box largest volume, we will have $\frac{dv}{dx}= 0$

$\frac{d (4x^{3} -92x^{2} +480x)}{dx} = \frac{dv}{dx}$

Differentiating the value

⇒ $\frac{dv}{dx} = 12x^{2} -184x+480$

taking out 12 as common in the equation and subtituting the value.

⇒ $0= 12(x^{2} -\frac{46x}{3} +40)$

solving quadratic equation inside the parenthesis.

⇒ $12(x^{2} -12x-\frac{10x}{x} +40)$ =0

Dividing 12 on both side

⇒ $[x(x-12)-\frac{10}{3} (x-12)]$ = 0

We can again take common as (x-12).

⇒ $x(x-12)[x-\frac{10}{3} ]$ =0

∴ $(x-\frac{10}{3} ) (x-12)= 0$

We have two value for x, which is $12 and \frac{10}{3}$

12 is invalid as, w= $(16-2x)= 16-2\times 12$

∴ 24 inches can not be cut out of 16 inches width.

Hence, the cut out size from cardboard is $\frac{10}{3}\ inches$

Now, subtituting the value of x to find volume of the box.

Volume(v)= $(30-2x)\times (16-2x)\times x$

⇒ Volume(v)= $(30-2\times \frac{10}{3} )\times (16-2\times \frac{10}{3})\times \frac{10}{3}$

⇒ Volume(v)= $(30-\frac{20}{3} ) (16-\frac{20}{3}) (\frac{10}{3} )$

∴ Volume(v)= 725.93 inches³

6 0

2 years ago

How do i solve this?

Damm [24]

From the ratio given you can determine that m is proportional to 1/(r^3). You can write this as m = k * 1/(r^3), k being your constant of proportionality. Then use this to calculate the next parts of the question.

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2 years ago