All categories

2 years ago

Subtract and simplify 1/2-1/3

Mathematics

2 answers:

frez [133]2 years ago

4 0

It’s gonna be 1/6 for this question!

aleksley [76]2 years ago

4 0

Answer:

1/6

Step-by-step explanation:

1/2 - 1/3

We need to get a common denominator of 6

1/2 *3/3 = 3/6

1/3 *2/2 = 2/6

3/6 - 2/6

1/6

You might be interested in

Tom is buying topsoil for the flower bed shown below. One bag of topsoil covers 151515 square meters. How many bags of topsoil d

exis [7]

Answer:

2 bags of topsoil.

Step-by-step explanation:

The attached figure shows a flower bed.

One bag of topsoil covers 15 square meters.

We need to find how many bags of topsoil does Tom need to cover his flower bed.

The area of the flower bed is :

$A=\dfrac{1}{2}\times 12\times 5\\\\=30\ m^2$

Let he has to cover x bags of topsoil. So,

x = Area of flower bed/Area of 1 bag of top soil

x = 30/15

x = 2

Hence, he will need 2 bags of topsoil to cover his flower bed.

6 0

2 years ago

How do I solve this

Kitty [74]

Hello,

$x^2-2x-27=-5x+1\\

x^2-2x+5x-27-1=0\\

x^2+3x-28=0\\

x^2+7x-4x-28=0\\

x(x+7)-4(x+7)=0\\

(x+7)(x-4)=0\\

x=-7\ or\ x=4\\
$

8 0

3 years ago

Read 2 more answers

10. Simplify the rational expression by rationalizing the denominator. 3 sqrt 160/sqrt 1350x A) 2 sqrt 15x/15x B) 3 sqrt 160/135

Viefleur [7K]

The simplified expression by rationalizing the denominator is (C) $\frac{4 \sqrt{15x} }{15x}$ .

First we must simplify the expression:
$\frac{3 \sqrt{160} }{\sqrt{1350x} } = \frac{12 \sqrt{10} }{15 \sqrt{6x} } = \frac{4 \sqrt{10} }{5 \sqrt{6x} }$

Then we factor the rational parts and cancel it out:
$\frac{4 \sqrt{2} \sqrt{5} }{5 \sqrt{2} \sqrt{3x} } = \frac{4\sqrt{5} }{5\sqrt{3x} }$

Then we rationalize the expression:
$\frac{4\sqrt{5} }{5\sqrt{3x} } * \frac{\sqrt{3x} }{\sqrt{3x} } = \frac{4 \sqrt{15x} }{5*3x} = \frac{4 \sqrt{15x} }{15x}$

<span>Finally, the simplified expression by rationalizing the denominator is (C) $\frac{4 \sqrt{15x} }{15x}$ .</span>

7 0

2 years ago

Paul travel to the lake and back. The trip took 3 hours and the trip back took 4 hours He averaged 10 mph faster on the trip the

ollegr [7]

Answer:

40 mph

Step-by-step explanation:

We assume "outbound" refers to the trip <em>to the lake</em>. The ratio of speeds is inversely proportional to the ratio of times, so ...

outbound speed : inbound speed = 4 : 3

These differ by one ratio unit, so that one ratio unit corresponds to the speed difference of 10 mph. Then the 4 ratio units of outbound speed will correspond to ...

4×10 mph = 40 mph

Paul's average speed on the outbound trip was 40 mph.

___

The distance to the lake was 120 mi.

4 0

2 years ago

Read 2 more answers

I wanted to see if i was right, can I get a second opinion?

Arisa [49]

15 tickets = $105

105 ÷ 15 = 7
1 ticket costs $7.

$7 x 12 = $84
12 tickets cost $84

Answer: $84 (Answer C)

6 0

3 years ago