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lorasvet [3.4K]
4 years ago
14

I need help with part B

Mathematics
1 answer:
lys-0071 [83]4 years ago
3 0
Okay, well with the information given, you can not come to an answer.  Is there something that shows all of the students who were in the survey?

Edit: Okay so there are 520 students in total.

We can say that the graph is equal to 520/520

However, we are trying to find how many of the 520 people voted for james.  We know that James received 15% of the votes.

Now, we can find 15% of 520 by taking 15/100 times 520.  The answer is 78.
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HELP
daser333 [38]

Answer:

cos

Step-by-step explanation:

take 31 degree as reference angle

using cos rule

cos 31=adjacent/hypotenuse

0.85=14/x

x=14/0.85

x=16.47

x=16.5

8 0
3 years ago
Read 2 more answers
5. What might be the dimensions of a<br> cylindrical container that holds 750 mL<br> of juice?
solmaris [256]

Answer:

radius of 10.9254843 and height of 10.9254843

Step-by-step explanation:

The equation for the volume of a cylinder is V = 2 pi r h

If V (volume) = 750, find for r and h

(I'm just going to make the radius and height the same thing)

750 = 2 pi r r

375 = pi r^2

119.366207 = r^2

10.9254843 = r

8 0
3 years ago
A collector bought a rare coin for $30. The coin is now valued at $37.50. What is the percent increase in value?​
AlladinOne [14]

Answer:

30

Step-by-step explanation:

5 0
3 years ago
Given that the circles are congruent, can you conclude that YZ=BC?<br> Answer options: yes, no
Anastasy [175]

Answer:

Answer is yes

Step-by-step explanation:

Given in the picture are two circles which are congruent.

This suggests that the radii of the two circles are equal.

Also the central angle of the two circles are congruent (given)

Consider triangles ABC and XYZ,

AC =XY:  AB = YZ:

Angle A = Angle X

By SAS theorem, the two triangles are congruent.

Hence BC = YZ

So yes is answer.

4 0
3 years ago
What is the equation of the line that passes through (-2,3) and is parallel to 2x+3y=6?
Vsevolod [243]

Answer:

<h2>2x + 3y = 5</h2>

Step-by-step explanation:

\bold{METHOD\ 1:}

The slope-intercept form of an equation of a line:

y=mx+b

<em>m</em><em> - slope</em>

<em>b</em><em> - y-intercept</em>

Let k:y=m_1x+b_1,\ l:y=m_2x+b_2

then

l\ \parallel\ k\iff m_1=m_2\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}

We have the equation of a line:

2x+3y=6

Convert to the slope-intercept form:

2x+3y=6           <em>subtract 2x from both sides</em>

3y=-2x+6              <em>divide both sides by 3</em>

y=-\dfrac{2}{3}x+2\to m_1=-\dfrac{2}{3}

therefore the slope is m_2=-\dfrac{2}{3}

Put the value of the slope and the coordinates of the point (-2, 3) to the equation of a line:

3=-\dfrac{2}{3}(-2)+b

3=\dfrac{4}{3}+b            <em>subtract 4/3 from both sides</em>

\dfrac{9}{3}-\dfrac{4}{3}=b\to b=\dfrac{5}{3}

Finally:

y=-\dfrac{2}{3}x+\dfrac{5}{3}

Convert to the standard form (Ax + By = C):

y=-\dfrac{2}{3}x+\dfrac{5}{3}              <em>multiply both sides by 3</em>

3y=-2x+5           <em>add 2x to both sides</em>

2x+3y=5

\bold{METHOD\ 2:}

Let k:A_1x+B_1y=C_1,\ l:A_2x+B_2y=C_2.

Lines <em>k</em> and <em>l</em> are parallel iff

A_1=A_2\ \wedge\ B_1=B_2\to\dfrac{A_2}{A_1}=\dfrac{B_2}{B_1}

We have the equation:

2x+3y=6\to A_1=2,\ B_1=3

then the equation of a line parallel to given lines has the equation:

2x+3y=C

Put the coordinates of the point (-2, 3) to the equation:

C=2(-2)+3(3)\\\\C=-4+9\\\\C=5

Finally:

2x+3y=5

4 0
3 years ago
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