PLEASE HELP I NEED IT VERY QUICKLY

10

liq [111]

Answer: 39.25

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Work Shown:

d = diameter = 10

r = radius = d/2 = 10/2 = 5

A = area of a full circle

A = pi*r^2 = 3.14*5^2 = 78.5

Cut this in half to get the area of a semicircle (aka half circle)

(78.5)/2 = 39.25

This result is approximate.

5 0

3 years ago

6p = -42 what is the answer???????????

Inga [223]

Answer:

Hey there!

Step 1:

$6p = - 42$

Write the equation

Step 2:

$p = \frac{ - 42}{6}$

take 6 to other side to divide it with-42

$p = - 7$

after dividing 6 with -42 we will get -7

$\small{\purple {\sf \underline{hope\: it\: helped\: you✿}}}$

8 0

3 years ago

Read 2 more answers

Gregory has 52 angelfish and 24 cichlid fish in his aquarium. Unfortunately, many of his fish got a sickness called "ick". 1/4 o

quester [9]

Answer:

21 fish

Step-by-step explanation:

52/4=13

24/3=8

13+8=21

3 0

3 years ago

Determine the ordered pair that satisfies the equation, 6x - 8y = 3.

vladimir2022 [97]

Answer:

B (-9,−57/8)

Step-by-step explanation:

we know that

If a ordered pair is a solution of the linear equation, then the ordered pair must satisfy the linear equation

we have

$6x-8y=3$

<u><em>Verify each case</em></u>

Substitute the value of x and the value of y in the linear equation and then compare the results

case A) (6,17/2)

For x=6, y=17/2

Substitute

$6(6)-8(17/2)=3$

$-32=3$ -----> is not true

therefore

The ordered pair not satisfy the equation

case B) (-9,-57/8)

For x=-9, y=-57/8

Substitute

$6(-9)-8(-57/8)=3$

$3=3$ -----> is true

therefore

The ordered pair satisfy the equation

case C) (6,-39/8)

For x=6, y=-39/8

Substitute

$6(6)-8(-39/8)=3$

$75=3$ -----> is not true

therefore

The ordered pair not satisfy the equation

case D) (6,-8)

For x=6, y=-8

Substitute

$6(6)-8(-8)=3$

$100=3$ -----> is not true

therefore

The ordered pair not satisfy the equation

4 0

4 years ago

Find (f - g)(x) if f(x) = x2 - x - 6 and g(x) = 2x2 - 3x + 4

Nadya [2.5K]

For this question we just have to re-substitute the expressions for their respective functions by assigning them in a plausible condition for two functions. Here, the first function of "x" is subtracted by a second function of "x". The expressions are assigned according to the first and second function expressions in each case or condition.

All we have to do is distribute the parentheses for second expression to deploy positive addition between 2x^2 and 3x. Furthermore grouping all the like terms to get the required answer to this query. So, let me express this via LaTeX interpreter equation editor for a better understanding and clear all the doubts for these forms of queries.

$\mathbf{Since, \: \: f(x) = x^2 - x - 6}$

$\mathbf{\therefore \quad \Big(x^2 - x - 6 - g(x) \Big) \: (x)}$

$\mathbf{Since, \: \: g(x) = 2x^2 - 3x + 4}$

$\mathbf{\therefore \quad x^2 - x - 6 - (2x^2 - 3x + 4)}$

$\mathbf{x^2 - x - 6 - (2x^2) - (- 3x) - (+ 4)}$

$\mathbf{x^2 - x - 6 - 2x^2 + 3x - 4}$

$\mathbf{x^2 - 2x^2 - x + 3x - 6 - 4}$

$\mathbf{x^2 - 2x^2 + 2x - 6 - 4}$

$\mathbf{- x^2 + 2x - 6 - 4}$

$\boxed{\mathbf{\underline{Required \: \: Answer: \: - x^2 + 2x - 10}}}$

Hope it helps.

6 0

3 years ago